代码语言:java publicbooleanwordBreak(Strings,Set<String>dict){intlen=s.length();boolean[]dp=newboolean[len+1];dp[0]=true;// 当前字符串:0~ifor(inti=1;i<=len;i++){// 将当前的字符串再进行拆分,查看它是否包含在 dict 中for(intj=0;j<i;j++){// dp[j] 是前面已经计算出来的结果if(...
1 class Solution { 2 public: 3 bool wordBreak(string s, unordered_set<string> &dict) { 4 vector<bool> dp(s.size()+1,false);//dp[i]表示从下标0开始的长度为i的子串能否满足word break; 5 dp[0] = true;//相当于分割成了空串和完整的字符串s。不能让dp[0]成为&&判断的绊脚石(&&右边如果...
代码如下: 1classSolution {2public:3boolwordBreak(strings, unordered_set<string> &dict) {4if(s.empty())returnfalse;5intlen =s.size();6unordered_set<string>::iterator end_it =dict.end();7vector<bool>dp(len);8if(dict.find(s.substr(0,1)) !=end_it){9dp[0] =true;10}else{11dp...
Can you solve this real interview question? Word Break II - Given a string s and a dictionary of strings wordDict, add spaces in s to construct a sentence where each word is a valid dictionary word. Return all such possible sentences in any order. Note
140. Word Break II Hard Topics Companies Given a string s and a dictionary of strings wordDict, add spaces in s to construct a sentence where each word is a valid dictionary word. Return all such possible sentences in any order. Note that the same word in the dictionary may be reused...
break; } } } return 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 14. 15. 16. 17. 18. 19. 20. 21. C#参考代码: AI检测 public class Solution { public bool WordBreak(string s, ISet<string> dict) { bool[] matches = new bool[s.Length + 1]; ...
题目链接:https://leetcode.com/problems/word-break-ii/ Given a string s and a dictionary of words dict, add spaces in s to construct a sentence where each word is a valid dictionary word. Return all such possible sentences. For example, given ...
Leetcode - Word Break II My code: 看了答案写出来的。 其实思路很简单。就是dfs + memory cache reference: https://discuss.leetcode.com/topic/27855/my-concise-java-solution-based-on-memorized-dfs/3 time complexity: O(len(wordDict) ^ len(s / minWord......
break; } } } return dp[0]; } } Word Break II Given a string s and a dictionary of words dict, add spaces in s to construct a sentence where each word is a valid dictionary word. Return all such possible sentences. For example, given s = "catsanddog", dict = ["cat", "cats"...
Leetcode Word Break Word Break Given a stringsand a dictionary of wordsdict, determine ifscan be segmented into a space-separated sequence of one or more dictionary words. For example, given s="leetcode", dict=["leet", "code"]. Return true because"leetcode"can be segmented as"leet code...