classSolution{public:intuniquePathsIII(vector<vector<int>>& grid){intm = grid.size(), n = grid[0].size(), x0 =0, y0 =0, target =1, res =0;for(inti =0; i < m; ++i) {for(intj =0; j < n; ++j) {if(grid[i][j] ==1) { x0 = i; y0 = j; }elseif(grid[i][...
Explanation: We have the following four paths: 1. (0,0),(0,1),(0,2),(0,3),(1,3),(1,2),(1,1),(1,0),(2,0),(2,1),(2,2),(2,3) 2. (0,0),(0,1),(1,1),(1,0),(2,0),(2,1),(2,2),(1,2),(0,2),(0,3),(1,3),(2,3) 3. (0,0),(1,0),(...
代码(Python3) class Solution: def uniquePaths(self, m: int, n: int) -> int: # dp[j] 表示从 (0, 0) 到 (i - 1, j - 1) 的不同路径数,初始化均为 0 。 # 这里使用了一维数组 + 临时变量的优化,能将空间复杂度从 O(mn) 降到 O(n) 。 dp: List[int] = [0] * (n + 1)...
Given the two integers m and n, return the number of possible unique paths that the robot can take to reach the bottom-right corner.The test cases are generated so that the answer will be less than or equal to 2 * 109.Example 1:Input: m = 3, n = 7 Output: 28 ...
class Solution(object): def uniquePaths(self, m, n): """ :type m: int :type n: int :rtype: int """ dp = [[1 for i in range(n)] for i in range(m)] for i in range(1, m): for j in range(1, n): dp[i][j] = dp[i-1][j] + dp[i][j-1] return dp[m-1]...
How many possible unique paths are there? Above is a 7 x 3 grid. How many possible unique paths are there? Note:mandnwill be at most 100. Example 1: 代码语言:javascript 代码运行次数:0 运行 AI代码解释 Input:m=3,n=2Output:3Explanation:From the top-left corner,there are a totalof3wa...
3,用到了i-1,j-1;所以用递增的方式 代码 代码语言:javascript 代码运行次数:0 funcuniquePaths(m int,n int)int{step:=make([][]int,m)fori:=0;i<m;i++{step[i]=make([]int,n)step[i][0]=1}fori:=0;i<n;i++{step[0][i]=1}fori:=1;i<m;i++{forj:=1;j<n;j++{step[i]...
63. Unique Paths II # 题目 # A robot is located at the top-left corner of a m x n grid (marked ‘Start’ in the diagram below). The robot can only move either down or right at any point in time. The robot is trying to reach the bottom-right corner of t
LeetCode 264 Ugly Number Medium Use 3 variables to store the current product for facter 2, 3, 5 respectively. LeetCode 62 Unique Paths Medium dp[i][j] = dp[i-1][j] + dp[i][j-1] LeetCode 63 Unique Paths II Medium The trasition equation is still dp[i][j] = dp[i-1][j]...
Unique Paths II Swift Medium O(mn) O(mn) Nested List Weight Sum II Swift Medium O(n) O(n) Flip Game II Swift Medium O(n) O(n) Can I Win Swift Medium O(2^n) O(n) Decode Ways Swift Medium O(n) O(n) Minimum Path Sum Swift Medium O(mn) O(mn) Generate Parentheses Swift ...