https://leetcode-cn.com/problems/unique-number-of-occurrences/ 耗时 解题:22 min 题解:4 min 题意 给你一个整数数组 arr,请你帮忙统计数组中每个数的出现次数。 如果每个数的出现次数都是独一无二的,就返回 true;否则返回 false。 思路 两个哈希表,一个用来离散统计出现次数,第二个测试出现次数是否独一...
Given an array of integersarr, write a function that returnstrueif and only if the number of occurrences of each value in the array is unique. Example 1: Input: arr = [1,2,2,1,1,3] Output: true Explanation: The value 1 has 3 occurrences, 2 has 2 and 3 has 1. No two values ...
第二次计数,同样声明一个长度为2001的int数组count2,如果count中的当前元素不等于0,就将当前元素作为count2数组的索引,元素值累加,加完后判断元素值是否大于等于2,如果大于,直接返回false。 publicbooleanuniqueOccurrences2(int[] arr){int[] count =newint[2001];for(intnum : arr) { count[num+1000]++; }...
Unique Number of Occurrences 独一无二的出现次数(Easy)(JAVA) 【LeetCode】 1207. Unique Number of Occurrences 独一无二的出现次数(Easy)(JAVA) 题目地址: https://leetcode.com/problems/unique-number-of-occurrences/ 题目描述: Given an array of integers arr, write a function that return......
Can you solve this real interview question? Unique Number of Occurrences - Given an array of integers arr, return true if the number of occurrences of each value in the array is unique or false otherwise. Example 1: Input: arr = [1,2,2,1,1,3] Outpu
相关企业 提示1 Check out the constraints, (maxSize <=26). 提示2 This means you can explore all substrings in O(n * 26). 提示3 Find the Maximum Number of Occurrences of a Substring with bruteforce. 相似题目 重排字符形成目标字符串 简单 评论(0) 贡献者 ...
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给你一个数组 arr ,请你将每个元素用它右边最大的元素替换,如果是最后一个元素,用 -1 替换。 完成所有替换操作后,请你返回这个数组。 示例1: 输入:arr = [17,18,5,4,6,1] 输出:[18,6,6,6,1,-1] 解释: - 下标 0 的元素 --> 右侧最大元素是下标 1 的元素 (18) ...
#defineMAXN1010booluniqueOccurrences(int*arr,int arrSize){int count[MAXN*2];int count_count[MAXN*2];memset(count,0,sizeof(count));memset(count_count,0,sizeof(count_count));int i=0;for(;i<arrSize;i++){count[arr[i]+MAXN]++;}for(i=0;i<MAXN*2;i++){count_count[count[i]]+...
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