classSolution{publicbooleanisSubstringPresent(String s){StringBuilder sb=newStringBuilder(s);String rev=sb.reverse().toString();int n=s.length();boolean flag=false;for(int i=0;i<n-1;i++){String sub=s.substring(i,i+2);if(rev.contains(sub)){flag=true;break;}}returnflag;}} ```...
public class Solution { /** * @param s: input string * @return: the longest palindromic substring */ public String longestPalindrome(String s) { // write your code here char[] S = s.toCharArray(); StringBuilder res = new StringBuilder("$#"); for (int i=0;i<S.length;i++){ res...
1publicString longestPalindrome(String s) {2intn =s.length();3String ans = "";4Set<String> set =newHashSet<String>();5for(inti = 0; i < n; i++) {6for(intj = i + 1; j <= n; j++) {7set.add(s.substring(i, j));8}9}10for(String m : set) {11if(isPalindromic(m...
提交网址:https://leetcode.com/problems/longest-palindromic-substring/ Total Accepted: 108823 Total Submissions: 469347 Difficulty: Medium Given a string S, find the longest palindromic substring in S. You may assume that the maximum length of S is 1000, and there exists one unique longest palind...
Minimum Deletions in a String to make it a Palindrome,怎么删掉最少字符构成回文 Palindromic Partitioning,怎么分配字符,形成回文 5. Longest Common Substring,最长子字符串系列,13个题 Longest Common Substring,最长相同子串 Longest Common Subsequence,最长相同子序列 Minimum Deletions & Insertions to Transform a...
Return the starting indices of all the concatenated substrings ins. You can return the answer inany order. usestd::collections::HashMap;implSolution{pubfnfind_substring(s:String,words:Vec<String>)->Vec<i32>{letwlen=words[0].len();lettotal=s.len();letword_count=words.len();letmutret=...
func minWindow(s string, t string) string { m := len(s) // count[ch] 表示滑动窗口 [l, r) 中字母 ch 还需出现的次数 count := make(map[byte]int) // 初始化为 t 中每个字母的出现次数 for _, ch := range t { count[byte(ch)] += 1 } // remain 表示滑动窗口 [l, r) 中还...
Can you solve this real interview question? Replace the Substring for Balanced String - You are given a string s of length n containing only four kinds of characters: 'Q', 'W', 'E', and 'R'. A string is said to be balanced if each of its characters appe
public int longestSubstring(String s, int k) { if (s.length() < k) return 0; HashMap<Character, Integer> counter = new HashMap(); for (int i = 0; i < s.length(); i++) { counter.put(s.charAt(i), counter.getOrDefault(s.charAt(i), 0) + 1); ...
*/publicclassSolution{publicintmyAtoi(String str){int len=str.length();// str.charAt(i) 方法回去检查下标的合法性,一般先转换成字符数组char[]charArray=str.toCharArray();// 1、去除前导空格int index=0;while(index<len&&charArray[index]==' '){index++;}// 2、如果已经遍历完成(针对极端用例 ...