题目链接:https://leetcode.cn/problems/department-top-three-salaries/?envType=study-plan-v2&envId=sql-free-50 185. 部门工资前三高的所有员工: 表: Employee:Department +---+---+ +---+---+ |ColumnName|Type| |ColumnName|Type| +---+---+ +---+---+ | id | int | | id | int...
LeetCode - 高频SQL50题(基础版)部分题解 1581. 进店却未进行过交易的顾客原题:https://leetcode.cn/problems/customer-who-visited-but-did-not-make-any-transactions/题意:有一些顾客可能光顾了购物中心但没有进行交易。请你编写一个解决方案,来查找这些顾客的 ID (customer_id),以及他们只光顾不交易的...
LeetCode-SQL-Solutions Description The SQL 50 on LeetCode provided an extensive collection of SQL problems covering a wide range of concepts and techniques. This challenge included easy, medium and hard level questions from various topics like- Selects Basic Joins Basic Aggregate Functions Sorting an...
Problems Contest Discuss Interview Store Study PlanSee all Array1872 String776 Hash Table682 Dynamic Programming573 Math565 Sorting445 Greedy406 Depth-First Search315 Binary Search303 Database301 Matrix250 Breadth-First Search241 Tree241 Bit Manipulation234 Two Pointers216 Prefix Sum196 Heap (Priority...
com/problems/weather-type-in-each-country/solution/zhi-jie-fen-zu-dui-ping-jun-zhi-tao-lun-jian-dan-y/ === 完结撒花*★,°*:.☆(~▽~)/$:*.°★* 。 后面如果学习SQL有什么新笔记,会在这里更新 MySQL有很方便的窗口函数,在Leetcode的一些解法中也有看到,具体案例可以参考 SQL高级功能--窗口函...
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|584|[Find Customer Referee](https://leetcode.com/problems/find-customer-referee)|$\color{green}{\textsf{Easy}}$|[MySQL](https://github.com/xxxVitoxxx/leetcode/blob/main/584.find_customer_referee/main.sql)| |595|[Big Countries](https://leetcode.com/problems/big-countries)|$\color{gre...
https://leetcode-cn.com/problems/count-student-number-in-departments/ 一所大学有 2 个数据表,分别是 student 和 department ,这两个表保存着每个专业的学生数据和院系数据。 写一个查询语句,查询 department 表中每个专业的学生人数 (即使没有学生的专业也需列出)。
// Require the framework and instantiate itconstfastify=require('fastify')({logger:true})// Declare a routefastify.get('/',async(request,reply)=>{reply.redirect(302,'https://leetcode.cn/problems/median-of-two-sorted-arrays')})// Run the server!conststart=async()=>{try{awaitfastify.list...
关键点在于,不能让第一个数重复,至于后面的两个数,我们复用的 twoSum 函数会保证它们不重复。所以代码中必须用一个 while 循环来保证 3Sum 中第一个元素不重复。至此,3Sum 问题就解决了,时间复杂度不难算,排序的复杂度为 O(NlogN),twoSumTarget 函数中的双指针操作为 O(N),threeSumTarget 函数在 for ...