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# 执行用时:535ms , 在所有 MySQL 提交中击败了69.86%的用户 内存消耗:0B , 在所有 MySQL 提交中击败了100.00%的用户 # https://leetcode.cn/problems/customers-who-never-order/solution/cong-bu-ding-gou-de-ke-hu-by-leetcode/ SQL 注释 MySQL -- 单行注释/* 多行注释 */ https://www.ibm.com...
Problems Contest Discuss Interview Store Study PlanSee all Array1872 String776 Hash Table682 Dynamic Programming573 Math565 Sorting445 Greedy406 Depth-First Search315 Binary Search303 Database301 Matrix250 Breadth-First Search241 Tree241 Bit Manipulation234 Two Pointers216 Prefix Sum196 Heap (Priority...
来源:力扣(LeetCode)链接:https://leetcode.cn/problems/all-the-pairs-with-the-maximum-number-of-common-followers #测试数据 Create table If Not Exists Relations (user_id int, follower_id int); insert into Relations (user_id, follower_id) values ('1', '3'); insert into Relations (user_...
链接:https://leetcode-cn.com/problems/monthly-transactions-ii 著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。 题解 两张表加tag字段区分,查询出需要的子段,并用union all合两张表(PS:union all不去重复数据行,union去重复行) 作为新表 ...
今天和大家聊的问题叫做重排链表,我们先来看题面: https://leetcode-cn.com/problems/reorder-list/ Given a singly linked list L: L0→L1→…→Ln-1→Ln, reorder it to: L0→Ln→L1→Ln-1→L2→Ln-2→… You may not modify the values in the list's nodes, only nodes itself may be chang...
链接:https://leetcode.cn/problems/all-the-pairs-with-the-maximum-number-of-common-followers #测试数据 Create table If Not ExistsRelations(user_id int,follower_id int);insert intoRelations(user_id,follower_id)values('1','3');insert intoRelations(user_id,follower_id)values('2','3');inser...
Write a SQL query to find all numbers that appear at least three times consecutively. For example, given the above Logs table, 1 is the only number that appears consecutively for at least three times. 三、参考SQL 方法一:多次连接 select distinct a.num as ConsecutiveNumsfrom Logs ainner join...
美国版的时候会出现问题,版本的原因美国版不能用邮箱,所以我选择cookie我们需要先下载nodejs 进入leetcode点击problems按F12并再次点击problems 按照途中顺序...cookie输入用户名或邮箱 复制刚复制的cookie回车即可 成功登陆 右键问题-show problem选择语言选择Just Open The problemfile即可 界面如上 编完码后点击 ...
union all select 'Programming' ) en left join experiments e on p.platform=e.platform and en.experiment_name = e.experiment_name group by p.platform, en.experiment_name; 82.低质量的问题 select problem_id from Problems where (likes / (likes + dislikes)) * 100 < 60 ...