题目1. 输出螺旋矩阵https://leetcode.com/problems/spiral-matrix/ 题目描述:顺时针方向输出螺旋矩阵,逐步螺旋进中心, 将元素按此顺序输出 题解: 略 java顺时针螺旋遍历M*N的矩阵 java顺时针螺旋遍历M*N的矩阵给定一个包含mxn个元素的矩阵(m行,n列),请按照顺时针螺旋顺序,返回矩阵中的所有元素。示例1:示例2...
Given anm x nmatrix, returnall elements of thematrixin spiral order. Example 1: Input: matrix = [[1,2,3],[4,5,6],[7,8,9]] Output: [1,2,3,6,9,8,7,4,5] Example 2: Input: matrix = [[1,2,3,4],[5,6,7,8],[9,10,11,12]] Output: [1,2,3,4,8,12,11,10,9,...
def spiralOrder(self, matrix):iflen(matrix) ==0:return[] r, c =len(matrix),len(matrix[0])ifc ==0:return[] roundr =0roundc =0res = []whileroundr < randroundc < c:foriinrange(roundc, c): res.append(matrix[roundr][i]) roundr +=1foriinrange(roundr, r): res.append(ma...
class Solution: def spiralOrder(self, matrix): """ :type matrix: List[List[int]] :rtype: List[int] """ # 如果矩阵为空,直接返回空 if not matrix: return [] # 结果数组,用来保存最终答案 res = [] # row表示行数,col表示列数 row, col = len(matrix), len(matrix[0]) # 第一行行...
本文始发于个人公众号: TechFlow,原创不易,求个关注 今天是 LeetCode专题的第32篇文章,我们一起看的是LeetCode的第54题——Spiral Matrix。 首先解释一下题意,这个Spiral是螺旋的意思,据说英文版的漫画里,…
Leetcode 题目解析之 Spiral Matrix II Given an integer n, generate a square matrix filled with elements from 1 to n2 in spiral order. For example, Given n = 3, You should return the following matrix: [ 1, 2, 3 , 8, 9, 4 ,
LeetCode-Spiral Matrix Description: Given a matrix of m x n elements (m rows, n columns), return all elements of the matrix in spiral order. Example 1: AI检测代码解析 Input: [ [ 1, 2, 3 ], [ 4, 5, 6 ], [ 7, 8, 9 ]...
Can you solve this real interview question? Spiral Matrix - Given an m x n matrix, return all elements of the matrix in spiral order. Example 1: [https://assets.leetcode.com/uploads/2020/11/13/spiral1.jpg] Input: matrix = [[1,2,3],[4,5,6],[7,8,9]]
【摘要】 Leetcode 题目解析之 Spiral Matrix Given a matrix of m x n elements (m rows, n columns), return all elements of the matrix in spiral order. For example, Given the following matrix: [ 1, 2, 3 , 4, 5, 6 , 7, 8, 9 ...
对于Spiral Matrix II, 这里我们只需要首先建立一个n*n的matrix,然后像I一样遍历即可。 上code class Solution(object): def generateMatrix(self, n): """ :type n: int :rtype: List[List[int]] """ if n == 0: return [] m, n = n, n ...