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LeetCode solutions. LeetCode solutions in English. LeetCode中文解答。 I uploaded some codes here Video solutions 中文解答 中文bilibili解答 Problem Video Solution LeetCode 1. Two Sum English 中文Youtube 中文b站 LeetCode 2. Add Two Numbers English 中文Youtube 中文b站 LeetCode 3. Longest Substring ...
Honesty Check: If I hit a roadblock within that timeframe, I'm not shy to peek at solutions on YouTube or Leetcode. Learning is the goal, right? Marathon Mentality: Remember, this is a marathon, not a sprint. Every day we pick up something new – that's the win. Solved Problems ...
Leetcode solutions for NeetCode.io github.com/neetcode-gh/ NeetCode.io 网站LeetCode试题题解 LeetCodeAnimation github.com/MisterBooo/L 用动画的形式呈现解LeetCode题目的思路 LeetcodeTop github.com/afatcoder/Le 汇总各大互联网公司容易考察的高频leetcode题 Interview Coder interviewcoder.co/ github.com...
我是一名计算机专业学生,希望系统学习算法,提升在 LeetCode 等平台上的解题水平。我主要使用 Java。 我的情况: 掌握Java 基础语法。 了解数组、链表、栈、队列,树、图较薄弱。 已做过约 50 道 LeetCode 题,多为 Easy 和部分 Medium。 每周学习时间:10~15 小时。
Java Solutions to problems on LintCode/LeetCode 0 stars 1.4k forks Branches Tags Activity Star Notifications coldly/LintCode master BranchesTags Code Folders and files Latest commit Cannot retrieve latest commit at this time. History346 Commits Java Others review .gitignore GenerateCode...
Follow up thought: if this is a system design question, how would you actually do it? Some read on how Youtube calculates total views. Solutions 代码语言:javascript 代码运行次数:0 运行 AI代码解释 importjava.util.HashMap;importjava.util.Map;importjava.util.PriorityQueue;importjava.util.Queue;pu...
Solutions 代码语言:javascript 代码运行次数:0 运行 AI代码解释 1publicList<Integer>spiralOrder(int[][]matrix){2List<Integer>res=newArrayList<>();34if(matrix==null||matrix.length==0||matrix[0].length==0){5returnres;6}78this.printSpiralOrder(0,0,matrix.length,matrix[0].length,res,matrix);...
Solutions Standard generic way Keep two stacks, operator and operands. When we see left bracket, keep pushing to the stack. We calculate the values as normal within the inner most bracket. When we see right bracket, calculate and pop out the left bracket ...
Solutions 1publicintmaxSideLength(int[][] mat,intthreshold) {2if(mat ==null|| mat.length == 0 || mat[0].length == 0) {3return0;4}5introw =mat.length;6intcol = mat[0].length;7//easier to implement with the initial value on the boarder to be 08int[][] prefixSum =newint...