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JCanary/Python-LeetCode-Solutionsmain 1 Branch0 Tags Code Folders and filesLatest commit JCanary Update Python - 13. Roman to Integer 1edd034· Mar 29, 2025 History31 Commits Python - 1. Two Sum Update Python - 1. Two Sum Feb 12, 2025...
classSolution:deftwoSum(self,nums:List[int],target:int)->List[int]:foriinrange(len(nums)):iftarget-nums[i]innums:return[i,nums.index[target-nums[i]]] 3)利用hash map加速搜索时间,啊哈,这个思路已经超出了我的理解范围,暂时想不出来了。 (3)参考Solutions 其实就是真正的Solutions啦,讲解的非常...
Then-queens puzzle is the problem of placingnqueens on ann×nchessboard such that no two queens attack each other. Given an integern, return all distinct solutions to then-queens puzzle. Each solution contains a distinct board configuration of then-queens' placement, where'Q'and'.'both indicat...
In the structure of the dictionary, solutions reside. 进一步拓展:其它解法 进一步思考:更简洁的写法,无序事先遍历元素创建字典 class Solution: def twoSum(self, nums: List[int], target: int) -> List[int]: # 创建一个空字典用于存储每个数及其对应的索引 dict = {} ## 不需要提前创建完整字典 #...
if i.val in p: #遍历另一个列表,如果某个元素在上面得到的dict中,则返回此元素 return i else: i=i.next return None other solutions given by leetcode: There are many solutions to this problem: Brute-force solution (O(mn) running time, O(1) memory): ...
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一. 树 1）求二叉树的高度（Maximum Depth of Binary Tree）// LeetCode, Maximum Depth of Binary ...
Python 代码:加入了记忆化搜索,即使用了缓存数组,以避免重复计算 memo=Nonedef_fib(n):ifmemo[n]!=-1:returnmemo[n]ifn==0:return0ifn==1:return1memo[n]=_fib(n-1)+_fib(n-2)returnmemo[n]deffib(n):globalmemo memo=[-1]*(n+1)return_fib(n) ...
方法6等同于Leetcode网站上的Solutions(JAVA)里提到的最优方法,不过这种方法固然是快,但思路不够自然,要考虑一堆犄角旮旯的case,现实里测试总是难保证覆盖全所有情况。从实践角度上来讲,使用的假设强度和性能需要有个平衡,因此我觉得方法5相对更好。 时间复杂度O(n) ...