minValue)) + minValue for i in range(int((maxSize + 1) * random.random()))] # 小数数组 arr = [random.random()*(maxValue-minValue)+minValue for i in range(int((maxSize+1) * random.random()))] return arr arr = generat
nsmallest(n, iterable, key=None) # 从堆中找出最小的 n 个数, 与 nlargest 相反 练习: LeetCode 703. Kth Largest Element in a Stream 4. 拓展 由于刷的题目尚少, 不知道以下的类以后会不会用到, 所以先列出, 等以后用到了再更新. array: 和list的一个重要区别, array只能存放指定的数据类型....
[LeetCode&Python] Problem 908. Smallest Range I Given an arrayAof integers, for each integerA[i]we may choose anyxwith-K <= x <= K, and addxtoA[i]. After this process, we have some arrayB. Return the smallest possible difference between the maximum value ofBand the minimum value of...
Given an arraynums, you are allowed to choose one element ofnumsand change it by any value in one move. Return the minimum difference between the largest and smallest value ofnumsafter perfoming at most 3 moves. Example 1: Input: nums = [5,3,2,4] Output: 0 Explanation: Change the ar...
*/funminSubArrayLen1(s:Int,nums:IntArray):Int{varans=Int.MAX_VALUEval n=nums.sizefor(iin0until n){// break to here, i++for(jini until n){varsum=0// 计算当前子数组的元素和for(kini..j){sum+=nums[k]}if(sum>=s){ans=min(ans,j-i+1)break// Found the smallest subarray with...
154Find Minimum in Rotated Sorted Array IIPythonBinary search with conditions, A[l] > A[r], A[l]=A[mid]=A[r] 155Min StackPythonJavaAdd another stack for min stack, maintance this stack when the main stack pop or push: 1. Only push min, such that len(minStack)<=len(Stack) 2...
1102.Path-With-Maximum-Minimum-Value (H-) 1631.Path-With-Minimum-Effort (H-) 1231.Divide-Chocolate (M) 1283.Find-the-Smallest-Divisor-Given-a-Threshold (M) 1292.Maximum-Side-Length-of-a-Square-with-Sum-Less-than-or-Equal-to-Threshold (H-) 1300.Sum-of-Mutated-Array-Closest-to-Target...
3）排序数组去重（Remove Duplicates from Sorted Array）// LeetCode, Remove Duplicates from Sorted ...
class Solution: def maxSlidingWindow(self, nums: List[int], k: int) -> List[int]: # 使用优先队列 # 注意 Python 默认的优先队列是小根堆,因此将数值边为负数,从而实现大根堆 q = [(-nums[i], i) for i in range(k)] heapq.heapify(q) # q = [(value, index)] n = len(nums) ans ...
LeetCode 刷题随手记 - 第一部分 前 256 题(非会员),仅算法题,的吐槽 https://leetcode.com/problemset/algorithms/...