minValue)) + minValue for i in range(int((maxSize + 1) * random.random()))] # 小数数组 arr = [random.random()*(maxValue-minValue)+minValue for i in range(int((maxSize+1) * random.random()))] return arr arr = generateRandomArray(maxSize=10, minValue=0, maxValue=1) print...
nsmallest(n, iterable, key=None) # 从堆中找出最小的 n 个数, 与 nlargest 相反 练习: LeetCode 703. Kth Largest Element in a Stream 4. 拓展 由于刷的题目尚少, 不知道以下的类以后会不会用到, 所以先列出, 等以后用到了再更新. array: 和list的一个重要区别, array只能存放指定的数据类型....
[LeetCode&Python] Problem 908. Smallest Range I Given an arrayAof integers, for each integerA[i]we may choose anyxwith-K <= x <= K, and addxtoA[i]. After this process, we have some arrayB. Return the smallest possible difference between the maximum value ofBand the minimum value of...
Given an array A of integers, for each integer A[i] we need to choose either x = -K or x = K, and add x to A[i] (only once).After this process, we have some array B.Return the smallest possible difference between the maximum value of B and the minimum value of B....
Leetcode题解-算法-数组与矩阵(python版) 1、把数组中的0移动到数组尾部 283. 移动零(Easy) 使用双指针,左指针指向当前已经处理好的序列的尾部,右指针指向待处理序列的头部。 右指针不断向右移动,每次右指针指向非零数,则将左右指针对应的数交换,同时左指针右移。
154Find Minimum in Rotated Sorted Array IIPythonBinary search with conditions, A[l] > A[r], A[l]=A[mid]=A[r] 155Min StackPythonJavaAdd another stack for min stack, maintance this stack when the main stack pop or push: 1. Only push min, such that len(minStack)<=len(Stack) 2...
154Find Minimum in Rotated Sorted Array IIPythonBinary search with conditions, A[l] > A[r], A[l]=A[mid]=A[r] 155Min StackPythonJavaAdd another stack for min stack, maintance this stack when the main stack pop or push: 1. Only push min, such that len(minStack)<=len(Stack) 2...
toArray(); int pre = toArray[0]; int res = Integer.MAX_VALUE; for (int i = 1; i < toArray.length; i++) { res = Math.min(res, toArray[i] - pre); pre = toArray[i]; } return res; } private static void dfs(TreeNode root, List<Integer> list) { if (root == null)...
3）排序数组去重（Remove Duplicates from Sorted Array）// LeetCode, Remove Duplicates from Sorted ...
Maximum Product of Word Lengths Given a string array`words`, find the maximum value of length`(word[i]) * length(word[j])`where the two words do not share common letters. You may assume that each word will contain only lower case letters. If no such two words exist, return 0. >...