LeetCode力扣 410. 分割数组的最大值 Split Array Largest Sum 110 -- 10:39 App LeetCode力扣 994. 腐烂的橘子 Rotting Oranges 112 -- 9:07 App LeetCode力扣 509. 斐波那契数 Fibonacci Number 38 -- 7:33 App LeetCode力扣 153. 寻找旋转排序数组中的最小值 Find Minimum in Rotated Sorted 130...
classSolution {public:intfindMinDifference(vector<string>&timePoints) {intres = INT_MAX, pre =0, first = INT_MAX, last =INT_MIN; vector<int> mask(1440,0);for(stringstr : timePoints) {inth = stoi(str.substr(0,2)), m = stoi(str.substr(3));if(mask[h *60+ m] ==1)return0;...
LeetCode: Minimum Time Difference Given a list of 24-hour clock time points in "Hour:Minutes" format, find the minimum minutes difference between any two time points in the list. Example 1: Input: ["23:59","00:00"] Output: 1 思路: 这个题目的思路还是比较简单的,找到两个间隔最小的时间...
classSolution { public:intfindMinDifference(vector<string>&timePoints) {intres = INT_MAX, pre =0, first = INT_MAX, last =INT_MIN; vector<int> mask(1440,0);for(stringstr : timePoints) {inth = stoi(str.substr(0,2)), m = stoi(str.substr(3));if(mask[h *60+ m] ==1)return0...
539 Minimum Time Difference Problem: Given a list of 24-hour clock time points in “Hour:Minutes” format, find the minimum minutes difference between any two time points in the list. Example Input: [“23:59”,”00:00”] Output: 1 ...
public: int findMinDifference(vector<string>& timePoints) { int res=INT_MAX; int n=timePoints.size(); sort(timePoints.begin(),timePoints.end()); for(int i=0;i<n;i++){ string t1=timePoints[i]; string t2=timePoints[(i+1)%n]; ...
https://leetcode.com/problems/minimum-absolute-difference/ 题目描述 Given an array of distinct integers arr, find all pairs of elements with the minimum absolute difference of any two elements. Return a list of pairs in ascending order(with respect to pairs), each...
Notes: It is guaranteed thatnumdoes not contain any leading zeros. The order of occurrence of the digits innum1andnum2may differ from the order of occurrence ofnum. Example 1: Input:num = 4325Output:59Explanation:We can split 4325 so thatnum1is 24 andnum2is 35, giving a sum of 59....
Leetcode 783: Minimum Distance Between BST Nodes 问题描述: Given the root of a Binary Search Tree (BST), return the minimum difference between the values of any two different nodes in the tree. 找出二叉搜索树中两个节点的最小差值 思路: 既然是二叉搜索树,则中序遍历可以获得升序排列的一组数...
Given a Binary Search Tree (BST) with the root node root, return the minimum difference between the values of any two different nodes in the tree. Example: Input: root = [4,2,6,1,3,null,null] Output: 1 Explanation: Note that root is a TreeNode object, not an array. The given ...