https://leetcode.com/problems/kth-largest-element-in-an-array/ Find the kth largest element in an unsorted array. Note that it is the kth largest element in the sorted order, not the kth distinct element. For example, Given [3,2,1,5,6,4] and k = 2, return 5. Note: You may ...
fromtypingimportListimportrandomclassSolution:deffindKthLargest(self,nums:List[int],k:int)->int:# 将问题转化为寻找第n-k个最小元素k=len(nums)-kdefquickSelect(l,r):pivot,p=nums[r],l# 将小于等于pivot的元素移动到左侧foriinrange(l,r):ifnums[i]<=pivot:nums[p],nums[i]=nums[i],nums[p...
Find the kth largest element in an unsorted array. Note that it is the kth largest element in the sorted order, not the kth distinct element.Example 1:Input: [3,2,1,5,6,4] and k = 2 Output: 5 Example 2:Input: [3,2,3,1,2,4,5,5,6] and k = 4 Output: 4 Note:...
Given an integer arraynumsand an integerk, returnthekthlargest element in the array. Note that it is thekthlargest element in the sorted order, not thekthdistinct element. Can you solve it without sorting? Example 1: Input:nums = [3,2,1,5,6,4], k = 2Output:5 Example 2: Input:nu...
215. Kth Largest Element in an Array 题目大意:给定无序数组求第k大,经典面试题 题目思路:利用快速排序,每次定一个轴,比轴大的放左边,小的放右边,如果左边的数量小于k,则第k大在右边,反之在左边,每次去找就好了 时间复杂度&&空间复杂度:O(n)(需要找的总共次数为n/2+n/4+…+1 = 2n-1...
https://leetcode.com/problems/kth-largest-element-in-an-array/ 题目: kth largest element in an unsorted array. Note that it is the kth largest element in the sorted order, not the kth distinct element. For example, Given[3,2,1,5,6,4] ...
Find the kth largest element in an unsorted array. Note that it is the kth largest element in the sorted order, not the kth distinct element. For example, Given [3,2,1,5,6,4] and k = 2, return 5. Note: You may assume k is always valid, 1 ≤ k ≤ array's length. ...
【题目】Find the kth largest element in an unsorted array. Note that it is the kth largest element in the sorted order, not the kth distinct element. For example, Given [3,2,1,5,6,4] and k = 2, return 5. Note: You may assume k is always valid, 1 ≤ k ≤ array’...
215. 数组中的第K个最大元素 - 给定整数数组 nums 和整数 k,请返回数组中第 k 个最大的元素。 请注意,你需要找的是数组排序后的第 k 个最大的元素,而不是第 k 个不同的元素。 你必须设计并实现时间复杂度为 O(n) 的算法解决此问题。 示例 1: 输入: [3,2,1,5,6,4]
for i in range(1, n): num = nums[i] if num > second: return True if num > first: second = num else: first = num return False 55. 跳跃游戏:给定一个非负整数数组 nums ,你最初位于数组的第一个下标。数组中的每个元素代表你在该位置可以跳跃的最大长度。判断你是否能够到达最后一个下标。