nums[p]#如果 p(位置) 大于 k,说明第 k 小的元素在 p 的左侧,因此算法递归地在左侧部分继续寻找ifp>k:returnquickSelect(l,p-1)elifp<k:returnquickSelect(p+1,r)else:returnnums[p]# 如果p正好是第k小的元素的索引,返回该元素# 随机打乱nums,以提高算法的平均性能,避免最坏情况random.shuffle(nums...
代码如下: importheapqclassSolution(object):deffindKthLargest(self, nums, k): min_heap = nums[:k] heapq.heapify(min_heap)# create a min-heap whose size is kfornuminnums[k:]:ifnum > min_heap [0]: heapq.heapreplace(min_heap , num)# or use:# heapq.heappushpop(min_heap, num)retu...
Find the kth largest element in an unsorted array. Note that it is the kth largest element in the sorted order, not the kth distinct element. Example 1: Input: [3,2,1,5,6,4] and k = 2 Output: 5 1. 2. Example 2: Input: [3,2,3,1,2,4,5,5,6] and k = 4 Output: 4 ...
636.Kth Largest Element in an Array 1.Problem Find thekth largest element in an unsorted array. Note that it is the kth largest element in the sorted order, not the kth distinct element. 题意很简单,找到一个一维数组中的第K大的数并返回。数组中第K大的数也是面试中经常考察的问题。现在就借...
[leetcode] 215. Kth Largest Element in an Array Description Find the kth largest element in an unsorted array. Note that it is the kth largest element in the sorted order, not the kth distinct element. Example 1: Input: [3,2,1,5,6,4] and k = 2...
博主Grandyang的c++解法:[LeetCode] 215. Kth Largest Element in an Array 数组中第k大的数字 开始的时候我的脑子里产生了很多天马行空的想法,比如用一个queue去重新存放顺序之类的。但是那显然是不合理且乱糟糟的。kth largest,就是一个排序问题。这里又一次用到了分治法,而且用到了快速排序里的左右互相交换...
LeetCode 0215. Kth Largest Element in an Array数组中的第K个最大元素【Medium】【Python】【快排】【堆】 Problem LeetCode Find thekth largest element in an unsorted array. Note that it is the kth largest element in the sorted order, not the kth distinct element. ...
Find the kth largest element in an unsorted array. Note that it is the kth largest element in the sorted order, not the kth distinct element. Example 1: Input: [3,2,1,5,6,4] and k = 2 Output: 5 Example 2: Input: [3,2,3,1,2,4,5,5,6] and k = 4 ...
https://leetcode.com/problems/kth-largest-element-in-an-array/description/ 内置排序beat 99%,重新写一下归并和快排比比试试。 自己写的归并排序,beat 40% . 快速排序由于基准点问题第一次直接 TLE. 好吧,修改一下,选取基准点的方法基本是: 1. 取左端或右端。 2. 随机取。 3. 取...
[p]=tmp2 p=i return p } func findKthLargest(nums []int, k int) int { start:=0 end:=len(nums)-1 //实际找的是第k-1小的数 , 因此在这里做了转换 //第k大的数 = 第len-k+1小的数 len=end+1 //然后实际是找第k-1索引处的数 , 因此为end+1-k+1-1 return findKthLargestIn(...