1. 如果target存在nums中,得到>=target的最左位置 2. 如果target存在nums中,得到>=target的最右位置 3. 如果target不存在nums中,得到>target的最左位置 4. 如果target不存在nums中,得到>target的最右位置 #解决情况1, 4 #情况1:因为nums[mid]==target,r位置会向左移动 #情况4:因为return l,返回的l是如果...
}publicstaticvoidmain(String[] args){SearchRangesearchRange=newSearchRange();int[] arr =newint[]{5,7,7,8,8,10}; System.out.println(Arrays.toString(searchRange.search(arr,8))); } }
publicclassSolution{publicint[]searchRange(int[]nums,inttarget){int[]result=newint[]{-1,-1};intstart=0;intend=nums.length-1;while(start<=end){intmiddle=(start+end)>>1;intmiddleValue=nums[middle];if(middleValue==target){//找到目标值后,先搜索其左边有没有与目标值相等的数,取其最左边的...
vector<int> searchRange3(int A[], int n, int target) { int mid = biSearch(A, 0, n-1, target); vector<int> res(2,-1); if (mid == -1) return res; int t = mid; for (t = mid; t > 0 && A[t] == A[t-1]; t--); res[0] = t; for (t = mid; t < n-1 ...
publicclassSolution{publicint[]searchRange(int[]A,inttarget){if(A==null||A.length==0)returnNOT_FOUND;returnsearch(A,target,0,A.length-1);}privateint[]search(int[]A,inttarget,intlow,inthigh){if(low>high)returnNOT_FOUND;if(low==high){if(A[low]==target)returnnewint[]{low,high};el...
int x=3;int p=upper_bound(nums.begin(),nums.end(),x)-nums.begin(); 灵活使用这两个函数可以应付绝大多数二分的问题,不仅可以简化代码量,也可以提高准确度。 好了,关于LeetCode刷题中常用的几个技巧就先分享到这里,如果大家还知道一些其他的技巧,欢迎在评论区补充。
class Solution { public: vector<int> searchRange(int A[], int n, int target) { vector<int> ret; if(A==NULL || n<=0) return ret; int first = getFirst(A, n, target); int last = getLast(A, n, target); ret.push_back(first); ret.push_back(last); return ret; } int get...
【leetcode】Search for a Range 题目描述: Given a sorted array of integers, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return[-1, -1]....
运行 AI代码解释 varsearch=function(fn,target){letleft=最小值,right=最大值;while(left<=right){// 取 mid 值constmid=((right-left)>>1)+left;//这里的 fn 可能是函数,也可能只是数组取值,反正就是可以取得一个值去跟 target 比较consttemp=fn(mid);if(temp===target)returnmid;if(temp<target)...
cells-in-a-range-on-an-excel-sheet cells-with-odd-values-in-a-matrix champagne-tower change-minimum-characters-to-satisfy-one-of-three-conditions check-array-formation-through-concatenation check-completeness-of-a-binary-tree check-distances-between-same-letters check-if-a-word-occurs-...