对于上面第二种解法,我们还可以再简化下,将求和和判断放在了一个循环中处理,依旧是做减法判断差值的奇偶,因为不满足条件就一直做累加,只有差值为偶数时才会退出循环。 publicintreachNumber(inttarget) { target = Math.abs(target);intresult =0,sum=0;while(sum< target || (sum-target)%2!=0) { result+...
You are standing at position 0 on an infinite number line. There is a goal at position target. On each move, you can either go left or right. During the n-th move (starting from 1), you take n steps. Return the minimum number of steps required to reach the destination. Example 1:...
拼多多笔试题Reach a Number--4行代码解决 LeetCode 754原题 Problem Desciption: You are standing at position 0 on an infinite number line. There is a goal at position target. On each move, you can either go left or right. During the n-th move (starting from 1), you take n step...
1+...-(sum-target+1)/2+...k=target-1 再考虑k的奇偶性。 3.1 如果k是偶数并且k>sum-target+1 那么1+...-(sum-target+1)/2+...-(k/2)...+k+(k+1)=target 相当于在1+2...+k+(k+1)减去了sum-target+1和k。 等价于sum+(k+1)-sum+target-1-k===>target也就是答案是k+1. ...
754. Reach a Number MultivacX 游戏开发者// LeetCode #302 medium // 754. Reach a Number // Runtime: 0 ms, faster than 100.00% of C++ online submissions for Reach a Number. // Memory Usage: 7.3 MB, less than 100.00% of C++ online submissions for Reach a Number. class Solution {...
Reference: https://leetcode.com/problems/reach-a-number/discuss/112968/Short-JAVA-Solution-with-Explanation 永远渴望,大智若愚(stay hungry, stay foolish)
754.Reacha Number You are standing at position 0 on an infinite number line. There is a goal at posit leetcode-java ide 原创 wx62ea2466cca9a 2022-08-03 21:05:55 78阅读 754.Reacha Number You are standing at position 0 on an infinite number line. There is a goal at position target...
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// discuss: https://leetcode.com/problems/minimum-jumps-to-reach-home/discuss/?currentPage=1&orderBy=most_votes&query=// submission codes start hereimpl Solution { pub fn minimum_jumps(forbidden: Vec<i32>, a: i32, b: i32, x: i32) -> i32 { ...
【leetcode】1292. Maximum Side Length of a Square with Sum Less than or Equal to Threshold 2019-12-23 10:33 −题目如下: Given a m x n matrix mat and an integer threshold. Return the maximum side-length of a square with a sum less than or e... ...