问题链接 英文网站:199. Binary Tree Right Side View中文网站:199. 二叉树的右视图问题描述Given the root of a binary tree, imagine yourself standing on the right side of it, return the values of the n…
Python: Compute the right view of both right and left left subtree, then combine them. For very unbalanced trees, this can be O(n^2), though. 1 2 3 4 5 6 defrightSideView(self, root): ifnotroot: return[] right=self.rightSideView(root.right) left=self.rightSideView(root.left) r...
* Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ class Solution { public List<Integer> rightSideView(TreeNode root) { List<Integer> result = new ArrayList<>(); if (root ==...
1/**2* Definition for a binary tree node.3* struct TreeNode {4* int val;5* TreeNode *left;6* TreeNode *right;7* TreeNode(int x) : val(x), left(NULL), right(NULL) {}8* };9*/10classSolution {11public:12vector<int> rightSideView(TreeNode*root) {13intdep = -1;14bfs(roo...
【LeetCode】199. Binary Tree Right Side View 解题报告(Python) 标签: LeetCode 题目地址:https://leetcode.com/problems/binary-tree-right-side-view/description/ 题目描述: Given a binary tree, imagine yourself standing on the right side of it, return the values of the nodes you can see ordered...
LeetCode199题 Binary Tree Right Side View, 解题思路。 1、先读题,凡是同一层的,有右边的节点,只添加右边的。 2、用bfs去解决,队列先添加右子树,再添加左子树,队列除了带node 信息,还得有当前层数的信息。 3、循环处理,当前层数没有被使用,就添加node的val。
if(curr.right!=null) s.push(curr.right); if(curr.left!=null) s.push(curr.left); } return res; } } Binary Tree Inorder Traversal Given a binary tree, return the inorder traversal of its nodes' values. For example: Given binary tree {1,#,2,3}, ...
Given a binary tree, return the preorder traversal of its nodes' values. For example: Given binary tree {1,#,2,3}, 代码语言:javascript 复制 1\2/3 return [1,2,3]. Note: Recursive solution is trivial, could you do it iteratively?
* Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */classSolution{public:TreeNode*invertTree(TreeNode*root){if(!root)returnroot;swap(root->right,root->left...
一. 树 1）求二叉树的高度（Maximum Depth of Binary Tree）// LeetCode, Maximum Depth of Binary ...