1/**2* Definition for a binary tree node.3* struct TreeNode {4* int val;5* TreeNode *left;6* TreeNode *right;7* TreeNode(int x) : val(x), left(NULL), right(NULL) {}8* };9*/10classSolution {11public:12vector<int> rightSideView(TreeNode*root) {13intdep = -1;14bfs(roo...
英文网站:199. Binary Tree Right Side View 中文网站:199. 二叉树的右视图 问题描述 Given therootof a binary tree, imagine yourself standing on theright sideof it, returnthe values of the nodes you can see ordered from top to bottom. Example 1: Input: root = [1,2,3,null,5,null,4] O...
Python: Compute the right view of both right and left left subtree, then combine them. For very unbalanced trees, this can be O(n^2), though. 1 2 3 4 5 6 defrightSideView(self, root): ifnotroot: return[] right=self.rightSideView(root.right) left=self.rightSideView(root.left) r...
今天和大家聊的问题叫做 二叉树的右视图,我们先来看题面:https://leetcode-cn.com/problems/binary-tree-right-side-view/ Given the root of a binary tree, imagine yourself standing on the right side of it, return the values of the nodes you can see ordered from top to bottom. 题意 给定一...
TreeNode left; //左子树 TreeNode right; //右子树 TreeNode() { } TreeNode(int val) { this.val = val; } TreeNode(int val, TreeNode left, TreeNode right) { this.val = val; this.left = left; this.right = right; } }
dfs(node.Right) } dfs(root)returnres } 🧠 思路总结 递归的核心是“做当前,交给子问题”,结构上非常清晰。 ✅ 解法二:迭代(用栈模拟) funcinorderTraversal(root *TreeNode)[]int{ res := []int{ } stack := []*TreeNode{ } curr := rootforcurr !=nil||len(stack) >0{forcurr !=nil{...
https://leetcode.com/problems/populating-next-right-pointers-in-each-node/ https://leetcode.com/problems/populating-next-right-pointers-in-each-node-ii/ https://leetcode.com/problems/binary-tree-right-side-view/ https://leetcode.com/problems/number-of-islands/ ...
if(curr.right!=null) s.push(curr.right); if(curr.left!=null) s.push(curr.left); } return res; } } Binary Tree Inorder Traversal Given a binary tree, return the inorder traversal of its nodes' values. For example: Given binary tree {1,#,2,3}, ...
LeetCode 每日一题 Daily Challenge 199 Binary Tree Right Side View 84 -- 5:48 App LeetCode 每日一题 Daily Challenge 1032 Stream of Characters 90 -- 1:45 App LeetCode 每日一题 Daily Challenge 100 Same Tree 250 -- 5:57 App LeetCode 每日一题 Daily Challenge 117 Populating Next Right ...
解答代码：```c int* twoSum(int* nums, int numsSize, int target, int* returnSize) { int* res = (int*)malloc(sizeof(int) * 2);*returnSize = 2;if (nums == NULL || numsSize < 2) { return res;} int HashMap[10000] = {0};for (int i = 0; i < numsSize; i++) { int...