link:[https://leetcode.com/explore/learn/card/data-structure-tree/134/traverse-a-tree/928/] 递归解法: #Definition for a binary tree node.#class TreeNode(object):#def __init__(self, x):#self.val = x#self.left = None#
[Leetcode]Binary Tree ivan.lv 机器学习|虚拟现实|人类语言-爱好者 来自专栏 · 编程基础 Graph View Binary Tree is a directed acyclic graph. 有向不循环图 Traversal Order pre-order / in-order / post-order(前/中/后 序)都是指 遍历时父节点的位置 post-order is widely used in the mathematical...
Same Tree: https://leetcode.com/problems/same-tree/ 这道题比较简单了。 View Code Maximum Depth of Binary Tree: https://leetcode.com/problems/maximum-depth-of-binary-tree/ 这道题应该算是leetcode中最简单的一道binary tree的题了。只要想清楚递归的关系就好。 View Code Unique Binary Search Tree:...
题目翻转二叉树 /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : ...
算法与数据结构基础 - 二叉树(Binary Tree) bangerlee 来自专栏 · 算法与数据结构基础 6 人赞同了该文章 二叉树基础 满足这样性质的树称为二叉树:空树或节点最多有两个子树,称为左子树、右子树, 左右子树节点同样最多有两个子树。 二叉树是递归定义的,因而常用递归/DFS的思想处理二叉树相关问题,例如LeetCode...
Leetcode 226. Invert Binary Tree \ to 代码语言:javascript 代码运行次数:0 4/\72/\/\9631 Trivia: This problem was inspired bythis original tweetbyMax Howell: Google: 90% of our engineers use the software you wrote (Homebrew), but you can’t invert a binary tree on a whiteboard so fuck...
Leetcode 之Binary Tree Postorder Traversal(44) 后序遍历,比先序和中序都要复杂。访问一个结点前,需要先判断其右孩子是否被访问过。如果是,则可以访问该结点;否则,需要先处理右子树。 vector<int> postorderTraversal(TreeNode *root) { vector<int>result;...
private void pushAllTheLeft(Stack<TreeNode> s, TreeNode root){ s.push(root); while(root.left!=null){ root = root.left; s.push(root); } } } Binary Tree Postorder Traversal Given a binary tree, return the postorder traversal of its nodes' values. ...
Leetcode 之Binary Tree Postorder Traversal(46) 采用广度优先遍历,一个变量记录层数,一个变量记录方向. voidtraverse(TreeNode *root, vector<vector<int>> result,intlevel,boolleft_to_right) {if(!root)return;//如果进入下一层了,则result同样也加一层if(level > result.size())result.push_back(vector<...
private void helper(TreeNode root, int depth){ if(depth>maxdepth){ maxdepth = depth; res.add(root.val); } if(root.right!=null) helper(root.right, depth+1); if(root.left!=null) helper(root.left, depth+1); } } 层序遍历 Level Order Traversal ...