classSolution:defremoveElement(self,nums:List[int],val:int)->int:i=0##从第一个元素开始whilei<len(nums):##遍历每一个元素ifnums[i]==val:nums.pop(i)##删除目标元素else:##继续前进i+=1returnnums,i##删掉最后一个的时候,i的取值就是非valnums的长度##顺便也把nums返回,查看效果 上面的 pop(...
Solution 1: intremoveElement(vector<int>& nums,intval) { /*set a new indexto to record new length, if it is val then jump to next element and do nothing, else, keep it. But there are some redundant assignment*/if(nums.empty())return0;intlength=0;for(inti=0;i<nums.size();i++...
Given an array and a value, remove all instances of that value in place andreturnthenewlength. The order of elements can be changed. It doesn't matter what you leave beyond thenewlength. 2.解法分析 这个题目稍微还有点意思,想出来解法之后感觉还比较巧妙。 classSolution { public: intremoveElemen...
solution=Solution2() print(solution.removeElements(nums1,2)) print(solution.removeElements(nums2,2)) print(solution.removeElements(nums3,2)) print(nums3) # 暴力法 class Solution: def removeElement1(self, nums: [int], val:int)->int: lens=len(nums) i=lens # 总共需要循环i次,即列表长度...
public class Solution { public int RemoveElement(int[] nums, int val) { int slow = 0; for (int fast = 0; fast < nums.Length; fast++) { if (nums[fast] != val) { nums[slow] = nums[fast]; slow++; } } return slow; } } C# 实现(首尾指针) public class Solution { public ...
classSolution { public: intremoveElement(intA[],intn,intelem) { intk = n-1; for(inti = 0; i <= k; i++) if(A[i] == elem) { while(k > i && A[k] == elem)k--;//从后面找到第一个不是elem的元素 if(k == i)returni; ...
The order of elements can be changed. It doesn't matter what you leave beyond the new length. 思路: 因为可以改变元素顺序,所以只需要把最后端的非val元素用最前端的val代替即可,前后两个指针同时移动直到相遇。 AC代码: 1classSolution {2public:3intremoveElement(vector<int>& nums,intval) {4inti=0...
public:intremoveElement(vector<int>& nums,intval) { autoiter= nums.begin();while(iter!= nums.end()){if(*iter== val)iter= nums.erase(iter);else++iter; }returnnums.size(); } }; 也可以不用erase函数,另一种解法如下: https://discuss.leetcode.com/topic/20654/a-simple-c-solution ...
Solution 1:暴力移动 1classSolution {2public:3intremoveElement(vector<int>& nums,intval){4intlen =nums.size();5intptr =0;6intnewLen =0;7for(inti =0;i<len;i++)8{9if(nums[i]!=val)10{11nums[ptr++]=nums[i];12}13}14newLen =ptr;15returnnewLen;16}17}; ...
classSolution {publicintremoveElement(int[] nums,intval) {if(nums ==null|| nums.length == 0)return0;intj = 0;for(inti = 0;i<nums.length;i++){if(nums[i] !=val){ nums[j]=nums[i]; System.out.println(nums[j]); j++;