*/functionpush($x){while(!$this->empty()) {$this->stack2[] =array_pop($this->stack1); }$this->stack1[] =$x;while(!empty($this->stack2)) {$this->stack1[] =array_pop($this->stack2); } }/** * Removes the element from in front of queue and returns that element. *@re...
## LeetCode 232## Impletement Queue using StackclassMyQueue:def__init__(self):self.l1=[]## stack 1 = l1self.l2=[]## stack 2 = l2defpush(self,x:int)->None:## Push x onto queueself.l1.append(x)## The right of the list = the top of the stack = the back of the queuedef...
StackIn: 作为缓存区,存储着待处理的元素 StackOut:作为输出栈,它负责提供队列头部的元素 同步异步操作 当StackOut中已有数据时,出队操作是异步的,可以立即执行,StackIn依旧可以执行它的入栈操作 当StackIn为空时,出队操作是同步的,需要等待stackIn中的所有元素转移至stackOut才能进行后续操作 判空状态 双栈均为空...
typeMyQueuestruct{// push 栈维护已放入的元素pushStack[]int// pop 栈维护待移除的元素。// 将 push 栈中的元素放入 pop 栈时,就将先进后出转换为了先进先出popStack[]int}funcConstructor()MyQueue{returnMyQueue{}}func(this*MyQueue)Push(xint){this.pushStack=append(this.pushStack,x)}func(this*MyQ...
Depending on your language, stack may not be supported natively. You may simulate a stack by using a list or deque (double-ended queue), as long as you use only standard operations of a stack. You may assume that all operations are valid (for example, no pop or peek operations will be...
Depending on your language, stack may not be supported natively. You may simulate a stack by using a list or deque (double-ended queue), as long as you use only standard operations of a stack. You may assume that all operations are valid (for example, no pop or peek operations will be...
/* * @lc app=leetcode id=232 lang=javascript * * [232] Implement Queue using Stacks *//** * Initialize your data structure here. */var MyQueue = function () { // tag: queue stack array this.stack = []; this.helperStack = [];};/** * Push element x to the back of ...
Depending on your language, stack may not be supported natively. You may simulate a stack by using a list or deque (double-ended queue), as long as you use only standard operations of a stack. You may assume that all operations are valid (for example, no pop or peek operations will be...
shiftStack();if(!_old.empty())return_old.top();return0; }//Return whether the queue is empty.boolempty(void) {return_old.empty() &&_new.empty(); }private: stack<int>_old, _new; }; 用栈来实现队列[LeetCode] Implement Queue using Stacks,如需转载请自行联系原博主。
Implement the following operations of a queue using stacks. push(x) -- Push element x to the back of queue. pop() -- Removes the element from in front of queue. peek() -- Get the front element. empty() -- Return whether the queue is empty. ...