40. Implement Queue by Two Stacks/225. Implement Stack using Queues 本题难度: Medium/Easy Topic: Data Structure - stack/queue Description As the title described, you should only use two stacks to implement a queue
Implement a last-in-first-out (LIFO) stack using only two queues. The implemented stack should support all the functions of a normal stack (push,top,pop, andempty). Implement theMyStackclass: void push(int x)Pushes element x to the top of the stack. int pop()Removes the element on t...
Queue<Integer> q;publicMyStack(){// int size():获取队列长度;//boolean add(E)/boolean offer(E):添加元素到队尾;//E remove()/E poll():获取队首元素并从队列中删除;//E element()/E peek():获取队首元素但并不从队列中删除。q =newLinkedList<>(); }publicvoidpush(intx){ q.add(x);fo...
## LeetCode 232classMyQueue:def__init__(self):self.l1=[]## queue1 = l1self.l2=[]## queue2 = l2defpush(self,x:int)->None:## Push x onto stackself.l1.append(x)## The right of the list = the top of the stack = the back of the queuedefpop(self)->int:## pop 抽取## ...
leetcode225 implement stack using queues 题目要求 Implement the following operations of a queue using stacks. push(x) -- Push element x to the back of queue. pop() -- Removes the element from in front of queue. peek() -- Get the front element....
题目链接:https://leetcode.com/problems/implement-stack-using-queues/题目: Implement the following operations of a stack using queues. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the top element. ...
LeetCode 225 Implement Stack using Queues 用队列实现栈,1、两个队列实现,始终保持一个队列为空即可2、一个队列实现栈
LeetCode 225. Implement Stack using Queues 简介:使用队列实现栈的下列操作:push(x) -- 元素 x 入栈;pop() -- 移除栈顶元素;top() -- 获取栈顶元素;empty() -- 返回栈是否为空 Description Implement the following operations of a stack using queues....
# Implement the following operations of a stack using queues. # # push(x) -- Push element x onto stack. # pop() -- Removes the element on top of the stack. # top() -- Get the top element. # empty() -- Return whether the stack is empty. # Notes: # You must use only ...
简介:Implement the following operations of a stack using queues.push(x) – Push element x onto stack.pop() – Removes the element on top of the stack.top() – Get the top element.empty() – Re Implement the following operations of a stack using queues. ...