map[key]= -1; } }/*** Your MyHashMap object will be instantiated and called as such: * MyHashMap obj = new MyHashMap(); * obj.put(key,value); * int param_2 = obj.get(key); * obj.remove(key);*/ 参考资料:N/A LeetCode 题目列表 -LeetCode Questions List...
b) 找到所有的起点，用HashMap来帮助记录每个节点的入度创建图，找到每个节点的入度a) 利用输入，把图...
Map<Integer, Integer> map =newHashMap<>();intresult = 0;for(intanswer : answers) {if(answer == 0) result++;elsemap.put(answer, map.getOrDefault(answer,0) + 1); }intgroupCount = 0;intleftover = 0;for(intkey : map.keySet()) {intvalue =map.get(key);intgroupSize = key + 1...
According to the definition of LCA on Wikipedia: “The lowest common ancestor is defined between two nodes p and q as the lowest node in T that has both p and q as descendants (where we allow a node to be a descendant of itself).” Given the following binary tree: root = [3,5,1...
这篇文章是关于LeetCode Top 100 Liked Questions 的 专栏记录,其中部分题目可能包括解题思路和多种优化解法。我把自己的思路都记录在这里,如果你看见了,请记得点个赞吧,蟹蟹【手动笑脸】。 1、Two Sum Given an array of integers, return indices of the two numbers such that they add up to a specific ...
以347 Top K Frequent Elements 为例,给定一个数组,求数组里出现频率最高的 K 个数字,比如对于数组 [1,1,1,2,2,3],K=2 时,返回 [1,2]。解决该问题的思路比较常规,首先用 hashmap 记录每个数字的出现频率,然后可以用 heap 来求出现频率最高的 k 个数字。
algorithmsleetcodeinterviewinterview-practiceleetcode-solutionsinterview-questionsleetcode-questionssorted-arraysleetcode-practiceleetcode-golangleetcode-go UpdatedJan 22, 2022 Go 推荐算法、相似度算法、布隆过滤器、均值算法、一致性Hash、数据结构、leetcode练习 ...
Hash Table Sort Bit Manipulation Union Find Sliding Window Segment Tree Binary Indexed Tree ♥️ Thanks LeetCode in Go LeetCode Online Judge is a website containing many algorithm questions. Most of them are real interview questions of Google, Facebook, LinkedIn, Apple, etc. and it always ...
从基础数据结构HashMap，HashSet，到TreeSet，TreeMap，Deque，LinkedHashMap；到各种对刷题来说的基础...
Hash Table Sort Bit Manipulation Union Find Sliding Window Segment Tree Binary Indexed Tree ♥️ Thanks LeetCode in Go LeetCode Online Judge is a website containing many algorithm questions. Most of them are real interview questions of Google, Facebook, LinkedIn, Apple, etc. and it always ...