链接:https://leetcode-cn.com/problems/first-missing-positive 分析: 要求时间复杂度为O(N),并且只能使用常数级别的空间 根据抽屉原理:数组的长度n,则答案最大只能是n+1; 可以使用hash函数将答案空间映射到长度为n+1的数组上,再遍历数组找到最小的没出现的正整数。 为实现常数空间复杂度,可以使用原数组的空间...
leetcode.com/problems/p leetcode.com/problems/p leetcode.com/problems/n leetcode.com/problems/c leetcode.com/problems/s leetcode.com/problems/s leetcode.com/problems/p leetcode.com/problems/c leetcode.com/problems/t leetcode.com/problems/l 11. Pattern: Modified Binary Search...
* MyHashMap obj = new MyHashMap(); * obj.put(key,value); * int param_2 = obj.get(key); * obj.remove(key); */ 04 第三种解法 使用单链表,此解法是参考至讨论区。传送门:https://leetcode.com/problems/design-hashmap/discuss/227081/Java-Solutions classMyHashMap{/** Initialize your da...
Node _next,Node _random) { val = _val; next = _next; random = _random; } }; */ public class Solution { // HashMap which holds old nodes as keys and new nodes as its values.
706Design HashMapEasySolution.java 707Design Linked ListMediumSolution.java 709To Lower CaseEasySolution.java 763Partition LabelsMediumSolution.java 771Jewels and StonesEasySolution.java 784Letter Case PermutationMediumSolution.java 797All Paths From Source to TargetMediumSolution.java ...
Answers for the leetcode problems Solutions MAY vary with offical LeetCode Solutions. PLEASE do a pull request for more elegant solutions(New Issue Request Template, make sure to read it!). Tips for beginners: If you are spending too much time on a problem, look and interpret the solutions...
publicclassSolution{publicbooleanisStrobogrammatic(String num){HashMap<Character,Character>map=newHashMap<Character,Character>();map.put('1','1');map.put('0','0');map.put('6','9');map.put('9','6');map.put('8','8');int left=0,right=num.length()-1;while(left<=right){//...
下面的思路借鉴自讨论区(https://leetcode.com/problems/maximum-xor-of-two-numbers-in-an-array/discuss/91049/Java-O(n%29-solution-using-bit-manipulation-and-HashMap)的一个解法。现在 Medium 的题目居然也需要看解答了,叹气。 代码语言:javascript 复制 class Solution { public int findMaximumXOR(int[...
350+Problems / 1000+Solutions 最好不要满足于accept，要追求最高效率。做一题就要杀死一题。leetcod...
保证斜率一致, 就是hashmap存储, 但是因为浮点误差的原因, 就用字符串保存, 两个数除去最大公约数, 进行保存, 每次开一个hashmap, 然后每次保存最大值. importjava.util.HashMap;importjava.util.Map;publicclassCode149{publicstaticintmaxPoints(int[][]points){int n=points.length,ans=1;for(int i=0;...