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This repository contains the solutions and explanations to the algorithm problems on LeetCode. Only medium or above are included. All are written in C++/Python and implemented by myself. The problems attempted multiple times are labelled with hyperlinks. Topics algorithms leetcode cpp Resources Re...
LeetCode All In One English | 简体中文 Provide all my solutions and explanations in Chinese for all the Leetcode coding problems. Same as this: LeetCode All in One 题目讲解汇总(持续更新中...) Click below image to watch YouTube Video Note: All explanations are written in Github Issues, ...
Therefore, when we face with a problem, we can first decide whether we can solve it in using backtracking by analyzing if its solution could be broken apart into partial solutions. (We will better understand the concept of partial candidate solution through practicing on some Leetcode problems) ...
2.https://leetcode-cn.com/problems/merge-two-sorted-lists/discuss/9735/Python-solutions-(iteratively-recursively-iteratively-in-place). 本文参与 腾讯云自媒体同步曝光计划,分享自作者个人站点/博客。 原始发表:2020/08/01 ,如有侵权请联系 cloudcommunity@tencent.com 删除 前往查看 java 编程算法 ...
比方说如果nums = [1,2,2],那么输出就是[[],[1],[1,2],[1,2,2],[2],[2,2]]。 对于这个问题,其实方法和上面很类似,我们也是考虑“选或不选”,然后遍历到最后一个元素就可以返回当前选择的子集。不过重复的可能性也是一样,即如果candidates = [2, 2],同样的子集[2],会被我们计算两次,所以需要...
350+Problems / 1000+Solutions 最好不要满足于accept,要追求最高效率。做一题就要杀死一题。leetcode不是给了运行时间的分布吗,基本上每个波峰都代表了一种特定复杂度的算法,中间的起伏体现的就是具体实现细节的差距。每次都要向最前面的波峰努力啊>.<。追逐最前一个波峰的过程不但锻炼算法,还锻炼数据结构,锻炼...
给你一个rows x cols大小的矩形披萨和一个整数k,矩形包含两种字符:'A'(表示苹果)和'.'(表示空白格子)。你需要切披萨k-1次,得到k块披萨并送给别人。 切披萨的每一刀,先要选择是向垂直还是水平方向切,再在矩形的边界上选一个切的位置,将披萨一分为二。如果垂直地切披萨,那么需要把左边的部分送给一个人,如...
350+Problems / 1000+Solutions 最好不要满足于accept，要追求最高效率。做一题就要杀死一题。leetcod...
return solutions[n]; } return 0; } };展开全部 4 回复 Return0 来自 北京 2024.11.25 贴一个带简单注释的c++代码 时空复杂度和官方一样 代码理解度高 class Solution { public: int ans = 0; void backtofind(unordered_set<int>& r, unordered_set<int>& p, unordered_set<int>& q, int n...