Python vezzolter/DSA Star8 Learn and practice the entire DSA in a simple and structured way with this C++ repository. learningcomputer-sciencealgorithmsleetcodecppdata-structures UpdatedMay 16, 2025 C++ naidu199/DSA Star3 DSA problems in Leetcode and Geeks for Geeks ...
This website is used to record the process of solving problems inLeetCode. On the one hand, I can develop a habit of solving problems, on the other hand, I can motivate myself to challenge difficulties one after another. If you are interested in it, please join us!
https://leetcode-cn.com/problems/house-robber/solution/yu-ni-yi-qi-xue-suan-fa-python3-shi-xian-knk6/ https://leetcode-cn.com/problems/house-robber-ii/solution/yu-ni-yi-qi-xue-suan-fa-python3-shi-xian-ifpb/ https://leetcode-cn.com/problems/house-robber/solution/da-jia-jie-she-by...
There is this awesome one line solution from this guy which is pretty insane. defspiralOrder(self, matrix):returnmatrixandlist(matrix.pop(0)) +self.spiralOrder(zip(*matrix)[::-1]) https://leetcode.com/problems/spiral-matrix/discuss/20571/1-liner-in-Python-%2B-Ruby Solutions 1publicList<...
Python:def test_1_wei_bag_problem(): weight = [1, 3, 4] value = [15, 20, 30] bag_weight = 4 # 初始化: 全为0 dp = [0] * (bag_weight + 1) # 先遍历物品, 再遍历背包容量 for i in range(len(weight)): for j in range(bag_weight, weight[i] - 1, -1): # 递归公式 ...
Level up your coding skills and quickly land a job. This is the best place to expand your knowledge and get prepared for your next interview.
leetcode接收订阅编程问题集锦塞巴斯蒂安·韦斯勒列表列表中最常出现的项目。两个排序列表中的公共元素。列表是另一个列表的轮换。公司航班预订-Leetcode1109[difference_array]寻找最佳价值。最接近目标的变异数组的总和。[binary_search]K离原点最近的点[快速排
python发送邮件 1.通过python发邮件步骤: 前提:开通了第三方授权,可以使用smtp服务 1.创建smtp对象 2.连接smtp服务器,默认端口号都是25 3.登陆自己的邮箱账号 4.调用发送消息函数,参数:发件人、收件人、消息内容 5.关闭连接 2.邮件消息注册: 首先创建一个消息对象: msg = email.mime.multipart.MIMEMultipart() ...
https://leetcode-cn.com/problems/group-anagrams/submissions/ 思路:将每个字符串排序一下,key=排序后的字符, value=原始的字符,放在map中即可 AC代码: classSolution{ publicList<List<String>>groupAnagrams(String[]strs) { Map<String,List<String>>map=newHashMap<>(); ...
树状数组 分治 Java Python 本题是「归并排序」的的经典问题 逆序对 的扩展问题(「力扣」上也有这道问题),实际上也是求逆序对,只不过要求输出的结果更具体:要求计算每一个元素的右边有多少个元素比自己小。问题1:为什么引入索引数组依然可以使用「归并排序」的「分而治之」的算法思想。接下来要解决的...