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NO.26 困难 (571. 给定数字的频率查询中位数) leetcode-cn.com/problem # 下面两种实现方式思路是一样的 # 首先,我们利用自连接的方法,求出小于等于该数字的数量top,再求出小于该数字的数量bottom。 # 然后因为中位数一定小于等于top,大于等于bottom,所以再筛选一下就得出结果。 # 当总数为偶数时,AVG就派上...
53. 最大子数组和 - 给你一个整数数组 nums ,请你找出一个具有最大和的连续子数组(子数组最少包含一个元素),返回其最大和。 子数组 是数组中的一个连续部分。 示例 1: 输入:nums = [-2,1,-3,4,-1,2,1,-5,4] 输出:6 解释:连续子数组 [4,-1,2,1] 的和最大,为
Can you solve this real interview question? Text Justification - Given an array of strings words and a width maxWidth, format the text such that each line has exactly maxWidth characters and is fully (left and right) justified. You should pack your word
目录No. Problem LeetCode 力扣 Python Go Solution Difficulty Tag 0017 Letter Combinations of a Phone Number LeetCode 力扣 Python CSDN Medium 回溯、暴力 0034 Find
请你设计并实现一个满足 LRU (最近最少使用) 缓存 约束的数据结构。 实现LRUCache 类: LRUCache(int capacity) 以正整数 作为容量 capacity 初始化 LRU 缓存 int get(int key) 如果关键字 key 存在于缓存中,则返回关键字的值,否则返回 -1。 void put(int key, int value) 如果关键字 key 已经存在,则变...
solution feat: add solutions to lc problem: No.2434 (#4465) Jun 6, 2025 .clang-format style: update format options Sep 6, 2022 .editorconfig chore: add configuration file .editorconfig (#3336) Jul 31, 2024 .gitignore chore: update .gitignore Apr 26, 2025 ...
testHead=testHead.next; } }if(!valid){break; }if(pre ==null){ pre=testHead; ret=pre; }else{ pre.next=testHead; } ListNode oldPre=current; ListNode next=current.next; current.next=testHead.next; pre=current; current=next;for(inti = 1; i < k; ++i){ ...
Problem # Given an array of words and a length L, format the text such that each line has exactly L characters and is fully (left and right) justified. # # You should pack your words in a greedy approach; that is, pack as many words as you can in each l JNingWei 2018/09/27 ...
将8皇后其中一个解垂直翻转后,可以得到一个新的解,故,可以只计算一半,从而加快时间。 N-Queens II 题目大意 计算解的个数 解题思路 不需要画图,有一个解就自增1 代码 代码语言:javascript 代码运行次数:0 运行 AI代码解释 classSolution(object):deftotalNQueens(self,n):""":type n:int:rtype:int""" ...