«leetcode problem 3sum »leetcode problem :23. Merge k Sorted Lists posted @2017-11-27 21:12nosaferyao阅读(168) 评论(0) <2025年4月> 日一二三四五六 303112345 6789101112 13141516171819 20212223242526 27282930123 45678910 昵称:nosaferyao ...
NO.20 简单 (511. 游戏玩法分析 I) leetcode-cn.com/problem # 按玩家ID分组,再取MIN(event_date)即可。 SELECT player_id, MIN(event_date) first_login FROM Activity GROUP BY player_id NO.21 简单 (595. 大的国家) leetcode-cn.com/problem # 简单 SELECT name, population, area FROM World ...
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53. 最大子数组和 - 给你一个整数数组 nums ,请你找出一个具有最大和的连续子数组(子数组最少包含一个元素),返回其最大和。 子数组 是数组中的一个连续部分。 示例 1: 输入:nums = [-2,1,-3,4,-1,2,1,-5,4] 输出:6 解释:连续子数组 [4,-1,2,1] 的和最大,为
Problem's Link # --- Mean: 题目意思太晦涩。 1 读出来 就是“1个1” 所以记为“11” 11 读出来 就是“2个1” 所以记为“21” 21 读出来 就是“1个2 1个1” 所以记为“1221” ... analyse: 略. Time complexity: O(N) view code 1....
Can you solve this real interview question? Text Justification - Given an array of strings words and a width maxWidth, format the text such that each line has exactly maxWidth characters and is fully (left and right) justified. You should pack your word
请你设计并实现一个满足LRU (最近最少使用) 缓存约束的数据结构。 实现LRUCache类: LRUCache(int capacity)以正整数作为容量capacity初始化 LRU 缓存 int get(int key)如果关键字key存在于缓存中,则返回关键字的值,否则返回-1。 void put(int key, int value)如果关键字key已经存在,则变更其数据值value;如果...
The Skyline Problem 219. Contains Duplicate II 220. Contains Duplicate III 222. Count Complete Tree Nodes 223. Rectangle Area 224. Basic Calculator 225. Implement Stack using Queues 226. Invert Binary Tree 229. Majority Element II 230. Kth Smallest Element in a BST 231. Power of Two 232. ...
Notes: It is intended for this problem to be specified vaguely (ie, no given input specs). You are responsible to gather all the input requirements up front. spoilers alert… click to show requirements for atoi. Requirements for atoi: The function first discards as many whitespace characters ...
2Branches21Tags Code README Code of conduct CC-BY-SA-4.0 license 介绍 本项目包含 LeetCode、《剑指 Offer(第 2 版)》、《剑指 Offer(专项突击版)》、《程序员面试金典(第 6 版)》等题目的相关题解。所有题解均由多种编程语言实现,包括但不限于:Java、Python、C++、Go、TypeScript、Rust。我们正在全力...