第78题. 子集 题目地址:https://leetcode-cn.com/problems/subsets/ 给定一组不含重复元素的整数数组 nums,返回该数组所有可能的子集(幂集)。 说明:解集不能包含重复的子集。 示例: 输入: nums = [1,2,3] 输出: [ [3], [1], [2], [1,2,3], [1,3], [2,3], [1,2], [] ] 思路 求...
class Solution(object): def subsets(self, nums): """ :type nums: List[int] :rtype: List[List[int]] """ # 初始为空集,之后没增加一个nums中的数字,则把res的所有都append这个数字 # 比如nums 1 2 3 ,初始res = [] 遍历到nums中的1则res ->[[],[1]] # 遍历到2 则res ->[[],[1...
Recursive (Backtracking) This is a typical problem that can be tackled by backtracking. Since backtracking has a more-or-less similar template, so I do not give explanations for this method. class Solution { public: vector<vector<int>> subsets(vector<int>& nums) {sort(nums.begin(), nums....
leetcode_medium_array problem 78. Subsets solution #1: code solution #2: 递归; 没看明白这种方法; code 参考 1. leetcode_78. Subsets; 完
Leetcode solution 772: Basic Calculator III Problem Statement Implement a basic calculator to evaluate a simple expression string. The expression string may contain open(and closing parentheses), the plus+or minus sign-,non-negative integers and empty spaces....
g++ -std=c++11 -Wall src/bar.cpp -o bar OR You can build all the files usingmake(Use MinGW GCC and GNU Make on Windows). The☢means that you need to have a LeetCode Premium Subscription. ProblemSolution 315Count of Smaller Numbers After Self ...
Baozi Training Leetcode solution 772 的主要算法是什么? 这个解决方案的时间复杂度是多少? 如何处理算式中的优先级问题? Problem Statement Implement a basic calculator to evaluate a simple expression string. The expression string may contain open ( and closing parentheses ), the plus + or minus sign...
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The n-queens puzzle is the problem of placing n queens on an n×n chessboard such that no two queens attack each other. Given an integer n, return all distinct solutions to the n-queens puzzle. Each solution contains a distinct board configuration of the n-queens' placement, where 'Q' ...