1publicclassSolution {2/**3*@paramA an integer array sorted in ascending order4*@paramtarget an integer5*@returnan integer6*/7publicintfindPosition(int[] nums,inttarget) {8if(nums ==null|| nums.length == 0) {9return-1;10}1112intstart = 0, end = nums.length - 1;13//要点1: st...
import java.util.Arrays; public class Main { public static void main(String[] args) { int[] citations1 = {3, 0, 6, 1, 5}; int result1 = hIndex(citations1); System.out.println(result1); // 输出:3 int[] citations2 = {1, 3, 1}; int result2 = hIndex(citations2); Syst...
class Solution: def maxNumber(self, nums1, nums2, k): def pick_max(nums, k): stack = [] drop = len(nums) - k for num in nums: while drop and stack and stack[-1] < num: stack.pop() drop -= 1 stack.append(num) return stack[:k] def merge(A, B): ans = [] while A...
Reference:https://discuss.leetcode.com/topic/27504/my-concise-java-solution-based-on-bfs-and-dfs importjava.util.ArrayList;importjava.util.HashMap;importjava.util.LinkedList;importjava.util.List;importjava.util.Queue;importjava.util.Set;publicclassWordLadderII {publicList<List<String>> findLadders(...
1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 分析 太简单了,略 提交结果 486. 预测赢家 给定一个表示分数的非负整数数组。 玩家 1 从数组任意一端拿取一个分数,随后玩家 2 继续从剩余数组任意一端拿取分数,然后玩家 1 拿,…… 。每次一个玩家只能拿取一个分数,分数被拿取之后不再可取。直到没有...
#TitleSolutionDifficultyAnalysis 306 Additive Number Java Medium 305 Number of Islands II Java Hard 304 Range Sum Query 2D - Immutable Java Medium 303 Range Sum Query - Immutable Java Easy 302 Smallest Rectangle Enclosing Black Pixels Java Medium 300 Longest Increasing Subsequence Java Medium...
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Could you do it in one-pass, using only O(1) extra memory and without modifying the value of the board? 【解答】要数有多少 battleship,并且要求使用 O(1) 的空间复杂度,还不能修改 board 上的数值。 一行一行遍历,每一行中从左往右遍历。对于每一个点,如果左侧和上方都不是 X,那就...
Problem description Given an integer array nums of unique elements, return all possible subsets (the power set). The solution set must not contain duplicate subsets. Return the solution in any order. Input: nums = [0,1,2] Output: [[],[0],[1],[0,1],[2],[0,2],[1,2],[0,1,...
Java classSolution{ publicintpartitionDisjoint(int[]nums){ intn=nums.length; int[]minn=newint[n+10]; minn[n-1]=nums[n-1]; for(inti=n-2;ii--) minn[i]=Math.min(minn[i+1],nums[i]); for(inti=0,maxx=0;in-1;i++){ maxx=Math.max(maxx,nums[i]); if(maxx=minn[i+1]) re...