res =log10(n)/log10(3);if(res- (int)res ==0)returntrue;elsereturnfalse;#endif}intmain(){intnum =4782968;boolres =false; res = isPowerOfThree(num);printf("res = %d\n",res);return0; }
Given an integer, write a function to determine if it is a power of three. Follow up: Could you do it without using any loop / recursion? 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 class Solution(object): def isPowerOfThree(self, n): """ :type n: int :...
Can you solve this real interview question? Power of Three - Given an integer n, return true if it is a power of three. Otherwise, return false. An integer n is a power of three, if there exists an integer x such that n == 3x. Example 1: Input: n
leetcode Power of Three题解 题目描述: Given an integer, write a function to determine if it is a power of three. Example 1: Example 2: Example 3: Example 4: 中文理解:给定一个数,判断则个数是不是3的幂次方。 解题思路:若n==0,返回false,如果n%3==0则n=n/3,最后返回n==1。 代码(...
Given an integer, write a function to determine if it is a power of three. Follow up: Could you do it without using any loop / recursion? 最直接的方法是使用log函数,还有一个从网上看到的别的方法,也可以,不过很难想。 建议和这一道题leetcode 342. Power of Four 4的幂指数 一起学习。
[leetcode]326. Power of Three problem 326. Power of Three solution: Iteration AI检测代码解析 class Solution { public: bool isPowerOfThree(int n) { if(n<1) return false;//err. while(n%3==0) { n /= 3; } return n==1;//err....
LeetCode笔记:342. Power of Four Given an integer (signed 32 bits), write a function to check whether it is a power of 4. Example: Given num = 16, return true. Given num = 5, return false. Follow up: Could you solve it without loops/recursion?
A valid additive sequence should contain at least three numbers. Except for the first two numbers, each subsequent number in the sequence must be the sum of the preceding two. For example: "112358" is an additive number because the digits can form an additive sequence: 1, 1, 2,...
2)Power of 3. 是否为3的幂指数 Loading...leetcode.com/problems/power-of-three/ 2.1)采用循环 classSolution:defisPowerOfThree(self,n:int)->bool:ifnotn:returnFalsewhilen:ifn==1:returnTrueifn%3:returnFalsen//=3returnTrue Runtime: 80 ms, faster than 52.08% of Python3 online submissio...
func isPowerOfThree(n int) bool { // 只要 n 是 3 ^ 0, 3 ^ 1, ..., 3 ^ 19 之一,就必定是 3 的幂次方。 // // 而 3 是质数,所以 3 ^ x 的所有因数都是 3 的幂次方, // 即只有 3 ^ 0, 3 ^ 1, ..., 3 ^ 19 能整除 3 ^ 19 , // 所以只要 n 能整除 3 ^ 19 ...