publicbooleanisPowerOfFour3(intnum){returnnum >0&& Integer.toString(num,4).matches("10*"); } 05 第四种解法 将4的所有幂次方整数放入一个HashSet中,然后判断num是否被包含在其中。 public boolean isPowerOfFour4(intnum) {Set<Integer>set=newHashSet<>(Arrays.asList(1,4,16,64,256,1024,4096,16...
【Leetcode】Power of Four 题目链接:https://leetcode.com/problems/power-of-four/题目: Given an integer (signed 32 bits), write a function to check whether it is a power of 4. Example: Given num = 16, return true. Given num = 5, return false. Follow up: Could you solve it without...
Given an integer (signed 32 bits), write a function to check whether it is a power of 4. Example: Given num = 16, return true. Given num = 5, return f
LeetCode-Power of Four Description: Given an integer (signed 32 bits), write a function to check whether it is a power of 4. Example 1: Input: 16 Output: true 1. 2. Example 2: Input: 5 Output: false 1. 2. Follow up:Could you solve it without loops/recursion? 题意:计算一个32...
2)Power of 3. 是否为3的幂指数 Loading...leetcode.com/problems/power-of-three/ 2.1)采用循环 classSolution:defisPowerOfThree(self,n:int)->bool:ifnotn:returnFalsewhilen:ifn==1:returnTrueifn%3:returnFalsen//=3returnTrue Runtime: 80 ms, faster than 52.08% of Python3 online submissio...
Leetcode 231. Power of Two (Python) Myron_yoo 21 0 Leetcode刷题 2 两数相加 Add Two Numbers JS老毕 2257 4 Leetcode力扣22 手画图解版|括号生成Generate Parentheses 爱学习的饲养员 4029 4 一周刷爆LeetCode,算法大神左神(左程云)耗时100天打造算法与数据结构基础到高级全家桶教程,直击BTAJ等一线...
一、题目 leetcode 上有这么一道题,power of three. 题目如下: Given an integer, write a function to deter...
请一键三连, 非常感谢LeetCode 力扣题解3254. 长度为 K 的子数组的能量值 I3254. Find the Power of K-Size Subarrays I帮你深度理解 滑动窗口 双指针算法 遍历循环 算法基础 编程技巧, 视频播放量 21、弹幕量 0、点赞数 0、投硬币枚数 0、收藏人数 0、转发人数 0, 视频作者
Given an integer, write a function to determine if it is a power of three. Follow up: Could you do it without using any loop / recursion?大意:给出一个整数,写一个函数来判断它是否是3的次方数。 进阶: 你能不能不用循环和递归来做?
class Solution: def isPowerOfThree(self, n: int) -> bool: # 只要 n 是 3 ^ 0, 3 ^ 1, ..., 3 ^ 19 之一,就必定是 3 的幂次方。 # #而 3 是质数,所以 3 ^ x 的所有因数都是 3 的幂次方, # 即只有 3 ^ 0, 3 ^ 1, ..., 3 ^ 19 能整除 3 ^ 19 , # 所以只要 n 能...