这样的话,显然array是一个比较好的选择。根据测试, 数字1和0都是对应空 “”。 2.因为是不同的组合,所以我们要从不同数字的对应字母里分别找出一个字母进行组合,这个就和leetcode里combination的题目很相似,应该用recursion来解 解题思路如下: 比如说我们输入23: 那么按照我们的习惯, 我们从2中的abc选一个a 再...
以后会更新对应的栈操作实现。 首先放出原题:Letter Combinations of a Phone Number Given a string containing digits from2-9inclusive, return all possible letter combinations that the number could represent. A mapping of digit to letters (just like on the telephone buttons) is given below. Note th...
Can you solve this real interview question? Letter Combinations of a Phone Number - Given a string containing digits from 2-9 inclusive, return all possible letter combinations that the number could represent. Return the answer in any order. A mapping o
"3":"def","4":"ghi","5":"jkl","6":"mno","7":"pqrs","8":"tuv","9":"wxyz"}foriinrange(len(list1)):list_temp=letter[list1[i]]list2.append(list_temp)#starttheloopfindallpossiblecombinationa=dyn_loop(list2)return
LeetCode 17. Letter Combinations of a Phone Number question output all the combination of the button combination input. algorithm using dfs to search all the possible combination. code...Leetcode 17. Letter Combinations of a Phone Number(python) 笨方法回溯啦 ......
1publicclassSolution {2privatestaticfinalString[] KEYS = { "", "", "abc", "def", "ghi", "jkl", "mno", "pqrs", "tuv", "wxyz"};34publicList<String>letterCombinations(String digits) {5List<String> res =newLinkedList<String>();6combination("", digits, 0, res);7returnres;8}91...
class LetterCombinationsPhoneNumber { func letterCombinations(_ digits: String) -> [String] { guard digits.count > 0 else { return [String]() } var combinations = [String](), combination = "" let numberToStr = ["", "", "abc", "def", "ghi", "jkl", "mno", "pqrs", "tuv",...
class LetterCombinationsPhoneNumber {func letterCombinations(_ digits: String) -> [String] {guard digits.count> 0else{return[String]()}var combinations = [String](), combination =""let numberToStr = ["","","abc","def","ghi","jkl","mno","pqrs","tuv","wxyz"]dfs(&combinations, ...
forletterinphone[next_digits[0]]: # append the current letter to the combination # and proceed to the next digits backtrack(combination+letter,next_digits[1:]) output=[] ifdigits: backtrack("",digits) returnoutput 1. 2. 3. 4.
Given a string containing digits from2-9inclusive, return all possible letter combinations that the number could represent. A mapping of digit to letters (just like on the telephone buttons) is given below. Note that 1 does not map to any letters. ...