string combination;backtrack(combinations, phoneMap, digits,0, combination);//核心方法-回溯returncombinations; }voidbacktrack(vector<string> &combinations, unordered_map<char,string> phoneMap,conststring& digits,intindex, string combination){if(index==digits.length()) {//已经走完一个分支combinations...
首先放出原题:Letter Combinations of a Phone Number Given a string containing digits from2-9inclusive, return all possible letter combinations that the number could represent. A mapping of digit to letters (just like on the telephone buttons) is given below. Note that 1 does not map to any ...
Can you solve this real interview question? Letter Combinations of a Phone Number - Given a string containing digits from 2-9 inclusive, return all possible letter combinations that the number could represent. Return the answer in any order. A mapping o
题目链接:https://leetcode.com/problems/letter-combinations-of-a-phone-number/ 题目: Given a digit string, return all possible letter combinations that the number could represent. A mapping of digit to letters (just like on the telephone buttons) is given below. AI检测代码解析 Input:Digitstring...
equals("")) { return new ArrayList<String>(); } List<String> ret = new LinkedList<String>(); combination("", digits, 0, ret); return ret; } private void combination(String prefix, String digits, int offset, List<String> ret) { //offset 代表在加哪个数字 if (offset == digits....
code: AI检测代码解析 classSolution{private:map<char,vector<char>>dict;vector<string>ret;public:voidcreateDict(){dict.clear();dict['2'].push_back('a');dict['2'].push_back('b');dict['2'].push_back('c');dict['3'].push_back('d');dict['3'].push_back('e');dict['3'].push...
(list_temp)*len(last))]#initialthelastcombinationifcur_y==0:last=list_templast_new=last.copy()else:num=0#combinationforiinrange(len(last)):forjinrange(len(list_temp)):last_new[num]=last[i]+list_temp[j]num=num+1cur_y=cur_y+1last=last_new.copy()dyn_loop(list2,cur_y,last)...
遍历每一位数字,同时遍历该数字所对应的字母,然后将对应字母进行叠加 每完成一次遍历,就将数字往后推一位,继续进行遍历 Python源码: classSolution:digit2letters={'2':"abc",'3':"def",'4':"ghi",'5':"jkl",'6':"mno",'7':"pqrs",'8':"tuv",'9':"wxyz",}defletterCombinations(self,digits...
>phoneDigits,int currentIndex,String combinationEntry,List<String>result){if(currentIndex==digits.length()){result.add(combinationEntry);return;}String currentLetters=phoneDigits.get(digits.substring(currentIndex,currentIndex+1));for(int i=0;i<currentLetters.length();i++){combinationEntry=combination...
这道题让我们求电话号码的字母组合,即数字2到9中每个数字可以代表若干个字母,然后给一串数字,求出所有可能的组合,相类似的题目有Path Sum II 二叉树路径之和之二,Subsets II 子集合之二,Permutations 全排列,Permutations II 全排列之二,Combinations 组合项,Combination Sum 组合之和和Combination Sum II 组合之和...