Next Letter (medium) Number Range (medium) Search in a Sorted Infinite Array (medium) Minimum Difference Element (medium) Bitonic Array Maximum (easy) 12. Pattern: Top ‘K’ Elements,前K个系列 任何让我们求解最大/最小/最频繁的K个元素的题,都遵循这种模式。 用来记录这种前K类型的最佳数据结构就...
publicintnextGreaterElement(intn) { char[] number = (n +"").toCharArray(); inti, j; // I) Start from the right most digit and // find the first digit that is // smaller than the digit next to it. for(i = number.length-1; i >0; i--) if(number[i-1] < number[i]) br...
Leetcode 901 Online Stock Span Leetcode 503 Next Greater Element II Leetcode 239 Sliding Window Maximum (唯一的单调队列题) 扫描线算法(Sweep Line) 基础知识:一个很巧妙的解决时间安排冲突的算法,本身比较容易些也很容易理解 常见题目: Leetcode 253 Meeting Room II(Meeting Room I也可以使用) Leetcode ...
1publicintremoveElement(int[] nums,intval) {2intindex=0;3for(inti =0; i<nums.length; i++){4if(nums[i] != val) nums[index++]=nums[i];5}6returnindex;7} 9、Next Permutation:数组表示一个整数,返回下一个排列数,如果没有比原数组大的排列数,则返回最小的排列数 1publicvoidnextPermutation...
this stack we are gonna to use is actually a mono decrease stack, and we store the element of nums1 as the key, and the final results as the value corresponding to that element in nums1. public int[] nextGreaterElement(int[] findNums, int[] nums) { ...
【题目】Say you have an array for which the i_th element is the price of a given stock on day _i. Design an algorithm to find the maximum profit. You may complete as many transactions as you like (ie, buy one and sell one share of the stock multiple times) with the followi...
monotonic stack: next greater / smaller 042.Trapping-Rain-Water (H) 255.Verify-Preorder-Sequence-in-Binary-Search-Tree (H) 496.Next-Greater-Element-I (H-) 503.Next-Greater-Element-II (H-) 654.Maximum-Binary-Tree (H) 739.Daily-Temperatures (H-) 768.Max-Chunks-To-Make-Sorted-II (H...
, int m, int B[], int n, int k) { //always assume that m is equal or smaller tha...
503 Next Greater Element II 46.20% Medium 502 IPO 32.40% Hard 501 Find Mode in Binary Search Tree 39.40% Easy 500 Keyboard Row 60.20% Easy 499 The Maze III 32.00% Hard 498 Diagonal Traverse 46.20% Medium 497 Random Point in Non-overlapping Rectangles 33.20% Medium 496 Next Greater Element ...
If no element exists, return an empty string "". Challenge: Perform all these in O(1) time complexity. 【解答】实现一个数据结构,加一、减一,获取最大值的 key 和最小值的 key,都是 O(1) 的时间复杂度。 这类题目可以说遇到多次了,有一些通用思路: 要O(1),根据 key 去取 value 的,无非...