find-nearest-point-that-has-the-same-x-or-y-coordinate find-peak-element find-pivot-index find-players-with-zero-or-one-losses find-positive-integer-solution-for-a-given-equation find-servers-that-handled-most-number-of-requests find-smallest-letter-greater-than-target find-the-city...
1779. Find Nearest Point That Has the Same X or Y Coordinate Feb 22, 2023 Find Numbers with Even Number of Digits Add all completed solutions Dec 28, 2021 Find Peak Element Add all completed solutions Dec 28, 2021 Find Pivot Index Add all completed solutions Dec 28, 2021 ...
1926-nearest-exit-from-entrance-in-maze 1929-concatenation-of-array 1937-maximum-number-of-points-with-cost 1962-remove-stones-to-minimize-the-total 1966-frequency-of-the-most-frequent-element 1971-find-if-path-exists-in-graph 1972-rotating-the-box 1973-count-nodes-equal-to-sum-of-descendants...
556. Next Greater Element IIIGiven a positive 32-bit integer n, you need to find the smallest 32-bit integer which has exactly the same digits existing in the integer nand is greater in value than n. If no such positive 32-bit integer exists, you need to return -1. Example 1: Input...
就是逐一遍历所有的cell,用分离的cell总的的边数减去重叠的边的数目即可。在查找重叠的边的数目的时候有一点小技巧,就是沿着其中两个方向就好,这种题目都有类似的规律,就是可以沿着上三角或者下三角形的方向来做。一刷一次ac,但是还没开始注意codestyle的问题,需要再刷一遍。
// Get the ID of t he bucket from element value x and bucket width w public int maxSubArray(int[] nums) { int max = Integer.MIN_VALUE; int sum = 0; for (int i = 0; i nums.length; ++i) { int cur = nums[i]; sum += cur; max = Math.max(max, sum); if (sum 0) ...
// https://leetcode.cn/problems/find-nearest-right-node-in-binary-tree/description/ // 1602. 找到二叉树中最近的右侧节点 #include<iostream> #include<queue> using namespace std; struct TreeNode { int val; TreeNode *left; TreeNode *right; TreeNode() : val(0), left(nullptr), right(null...
D. Remove One Element (1500) DP E. Nearest Opposite Parity (1900) 反向+多源dfs F. Two Bracket Sequences (2200) dp Codeforces Round #611 (Div. 3) A. Minutes Before the New Year (800) B. Candies Division (900) C. Friends and Gifts (1500) D. Christmas Trees (1800) (BFS...
The first element is always larger than its next one while the second element is always smaller than its previous one. 思路来自于:https://discuss.leetcode.com/topic/3988/no-fancy-algorithm-just-simple-and-powerful-in-order-traversal/2
1779 Find Nearest Point That Has the Same X or Y Coordinate C++ Easy 1775 Equal Sum Arrays With Minimum Number of Operations C++ Medium 1774 Closest Dessert Cost C++ Medium 1773 Count Items Matching a Rule C++ Easy 1771 Maximize Palindrome Length From Subsequences C++ Hard 1770 Maximum Score fr...