Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array. Note: The number of elements initialized in nums1 and nums2 are m and n respectively.You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional...
Note:You may assume that A has enough space (size that is greater or equal tom+n) to hold additional elements from B. The number of elements initialized in A and B aremandnrespectively. 解法一:从前往后,小的排最前。每次插入一个B,A需要整体后移。 classSolution {public:voidmerge(intA[],i...
代码(Python3) class Solution: def merge(self, nums1: List[int], m: int, nums2: List[int], n: int) -> None: """ Do not return anything, modify nums1 in-place instead. """ # i/j 分别表示 nums1/nums2 中还未使用的最大数的下标 i, j = m - 1, n - 1 # k 表示 nums...
Given two sorted integer arraysnums1andnums2, mergenums2intonums1as one sorted array. Note: You may assume thatnums1has enough space (size that is greater or equal tom+n) to hold additional elements fromnums2. The number of elements initialized innums1andnums2aremandnrespectively. 这道题很...
class Solution { public: void merge(int A[], int m, int B[], int n) { int ia = m - 1, ib = n - 1, icur = m + n - 1; while(ia >= 0 && ib >= 0) A[icur--] = A[ia] > B[ib] ? A[ia--] : B[ib--]; ...
LeetCode: 88. Merge Sorted Array LeetCode: 88. Merge Sorted Array 题目描述 Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array. Note: You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional ...
LeetCode 88. 合并两个有序数组 Merge Sorted Array Table of Contents 一、中文版 二、英文版 三、My answer 四、解题报告 一、中文版 给你两个有序整数数组 nums1 和 nums2,请你将 nums2 合并到 nums1 中,使 nums1 成为一个有序数组。
88. Merge Sorted ArrayEasy Topics Companies Hint You are given two integer arrays nums1 and nums2, sorted in non-decreasing order, and two integers m and n, representing the number of elements in nums1 and nums2 respectively. Merge nums1 and nums2 into a single array sorted in non-...
地址:Merge Sorted Array 代码 /** * @param {number[]} nums1 * @param {number} m * @param {number[]} nums2 * @param {number} n * @return {void} Do not return anything, modify nums1 in-place instead. */ var merge = function(nums1, m, nums2, n) { var i; if(m===0)...
地址:Merge Sorted Array 代码 /** * @param {number[]} nums1 * @param {number} m * @param {number[]} nums2 * @param {number} n * @return {void} Do not return anything, modify nums1 in-place instead. */ var merge = function(nums1, m, nums2, n) { var i; if(m===0)...