// Space Complexity: O(1) publicStringlongestPalindrome(String s){ // 1 <= s.length <= 1000 // if (s.isEmpty()) return ""; // 与 char 数组相比,s.charAt(i) 会进行数组下标越界等检查,因此转为 char 数组会更高效 // 使用 String:176ms // 转为
class Solution { public: string longestPalindrome(string s) { int len = s.size(); int longest = 0, left = 0, right = 0;//最长长度,左界,右界 vector<vector<bool>> dp(len, vector<bool>(len, false)); for (int i = len - 1; i >= 0; --i) { for (int j = i; j < le...
substr(begin, longest); } }; 作者:saul-9 链接:https://leetcode-cn.com/problems/longest-palindromic-substring/solution/yun-xing-shi-jian-0msji-bai-100de-da-an-by-saul-9/ 来源:力扣(LeetCode)著作权归作者所有。商业转载请联系作者获得授权,非商业转载请注明出处。 本文参与 腾讯云自媒体同步曝光...
提交网址:https://leetcode.com/problems/longest-palindromic-substring/ Total Accepted: 108823 Total Submissions: 469347 Difficulty: Medium Given a string S, find the longest palindromic substring in S. You may assume that the maximum length of S is 1000, and there exists one unique longest palind...
Given a string s, find the longest palindromic substring in s. You may assume that the maximum length of s is 1000. Example 1: Input: "babad" Output: "bab" Note: "aba" is also a valid answer. Example 2: Input: "cbbd" Output: "bb" 题意: 给一个字符串s,找到最长回文串,回文串...
Given a string s, find the longest palindromic substring in s. You may assume that the maximum length of s is 1000. 给定字符串 s,找到 s 中最长的回文字符串,可以假定 s 的最大长度是 1000。 Example 1: Input: "babad" Output: "bab" Note: "aba" is also a valid answer. Example 2:...
Can you solve this real interview question? Longest Palindromic Substring - Given a string s, return the longest palindromic substring in s. Example 1: Input: s = "babad" Output: "bab" Explanation: "aba" is also a valid answer. Example 2: Input
LeetCode-Longest Palindromic Substring Description: Given a string s, find the longest palindromic substring in s. You may assume that the maximum length of s is 1000. Example 1: Input: “babad” Output: “bab” Note: “aba” is also a valid answer....
一发现不满足的情况立即break进行下一个中心字符的推断,代码例如以下: class Solution { public: string longestPalindrome(string s) { string ans; int len=s.length(); int maxLength=-1,CurLen,Sbegin; for(int i=0;i<len;i++) { int left=i-1,right=i+1; while(left>=0&&right<len&&s[left]...
Given a string S, find the longest palindromic substring in S. You may assume that the maximum length of S is 1000, and there exists one unique longest palindromic substring. 暴力法 Brute Force 复杂度 时间O(n^3) 空间 O(1) 思路