Can you solve this real interview question? Longest Palindromic Substring - Given a string s, return the longest palindromic substring in s. Example 1: Input: s = "babad" Output: "bab" Explanation: "aba" is also a valid answer. Example 2: Input
* @return */publicstaticStringlongestPalindrome(String s){if(s==null||s.length()<2){returns;}int maxLength=0;String longest=null;int length=s.length();boolean[][]table=newboolean[length][length];// 单个字符都是回文for(int i=0;i<length;i++){table[i][i]=true;longest=s.substring(i...
一.题目链接:https://leetcode.com/problems/longest-palindromic-substring/ 二.题目大意: 给定一个字符串,找出它最长的回文子串。例如,字符串“caabb”,它的最长回文子串为“aabb”。 三.题解: 找最长回文子串应该说是比较经典的题目,这个题目我目前有三种思路: 方法1:暴力解决,找出所有的子串,并判断子串是不...
publicStringlongestPalindrome(String s){intmax=0, n = s.length();Stringresult="";for(inti=0; i<n; i++) {for(intj=i+1; j<=n; j++) {Stringtem=s.substring(i,j);if(isPalindrome(tem)) {if(j-i > max) { max = j-i; result = tem; } } } }returnresult; }publicbooleanisP...
public String longestPalindrome(String s) { // 改造字符串,每个字符间添加#。添加头^尾$两个不同的字符用于消除边界判断 StringBuilder sb = new StringBuilder("^"); for (int i = 0, len = s.length(); i < len; i++) sb.append("#").append(s.charAt(i)); sb.append("#$"); int c ...
(2)中心扩展法。复杂度O(N²) 枚举每个字符作为中心点向左右扩展。 可是这里要注意,对于每一次扩展要分奇偶两种情况。 否则可能会漏掉情况。 一发现不满足的情况立即break进行下一个中心字符的推断,代码例如以下: class Solution { public: string longestPalindrome(string s) { string ans; int len=s.length...
def longestPalindrome(self, s: str) -> str: # if s == s[::-1]: return s l, ms = len(s), '' if l < 2: return s # 比第一行更优点 #l, m, ms = len(s), 1, s[0] # m 最大长度 ms 最长子串 for i in range(l): ...
Given a string s which consists of lowercase or uppercase letters, return the length of the longest palindrome that can be built with those letters.Letters are case sensitive, for example, "Aa" is not considered a palindrome here. 英文版地址 leetcode.com/problems/l 中文版描述 给定一个包含大...
classSolution {public:stringlongestPalindrome(strings) { size_t slen=s.length();if(slen <2)returns;//inserting tokens to original stringstringns ="#";for(auto c : s) { ns+=c; ns+="#"; }//size_t len =ns.length(); vector<size_t> rec(len,0);intmaxi =1, maxr =0;intci =...
publicStringlongestPalindrome(String s){// Your Code} 题目分析 该题目是字符串类型的Medium题目,要求找到字符串中最长的回文子串(LeetCode 3的题目中解释了substring和subsequence的区别),回文串就是顺序和逆序相同的字符串,如Examples所示。最朴素的想法是找到字符串的所有子串,查看每个子串是否是回文串,这种算法的...