* TreeNode(int x) : val(x), left(NULL), right(NULL) {} * };*/classSolution {public: vector<int> inorderTraversal(TreeNode *root) { vector<int>ret;if(!root)returnret; inorder(root, ret);returnret; }voidinorder(TreeNode* root, vector<int>&ret) {if(root->left) inorder(root-...
Given a binary tree, return theinordertraversal of its nodes' values. For example: Given binary tree{1,#,2,3}, 1 \ 2 / 3 return[1,3,2]. Note:Recursive solution is trivial, could you do it iteratively? confused what"{1,#,2,3}"means? > read more on how binary tree is seriali...
class Solution { public: vector<int> inorderTraversal(TreeNode *root) { // Start typing your C/C++ solution below // DO NOT write int main() function vector<int> *p_vec = new vector<int>(); inorderRecur( root, *p_vec); return *p_vec; } void inorderRecur( TreeNode *root, vecto...
Binary Tree Inorder Traversal Given a binary tree, return the inorder traversal of its nodes' values. For example: Given binary tree {1,#,2,3}, 1 \ 2 / 3 return [1,3,2]. Note: Recursive solution is trivial, could you do it iteratively? confused what "{1,#,2,3}" means? > ...
iterativeInorder(node) parentStack=empty stackwhile(notparentStack.isEmpty()ornode ≠ null)if(node ≠ null) parentStack.push(node) node=node.leftelsenode=parentStack.pop() visit(node) node= node.right Python解法 classSolution(object):definorderTraversal(self, root):#迭代""":type root: Tree...
Solution classSolution{private:voidrecursiveBuild(TreeNode* &node, vector<int>& preorder,intpstart,intpend, vector<int>& inorder,intistart,intiend){if(pstart > pend)return; node =newTreeNode(preorder[pstart]);if(pstart == pend)return;inti;for(i = istart; i <= iend; i++)if(inord...
Given a binary tree, return theinordertraversal of its nodes' values. For example: Given binary tree{1,#,2,3}, 1 \ 2 / 3 return[1,3,2]. Note: Recursive solution is trivial, could you do it iteratively? 中序遍历二叉树,递归遍历当然很容易,题目还要求不用递归,下面给出两种方法: ...
Given preorder and inorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree. 说明: 1)二叉树可空 2)思路:a、根据前序遍历的特点, 知前序序列(PreSequence)的首个元素(PreSequence[0])为二叉树的根(root), 然后在中序序列(InSequence...
【Inorder Traversal】 Given a binary tree, return theinordertraversal of its nodes' values. For example: Given binary tree{1,#,2,3}, 1 \ 2 / 3 return[1,3,2]. Note:Recursive solution is trivial, could you do it iteratively?
下面这种解法跟Binary Tree Preorder Traversal中的解法二几乎一样,就是把结点值加入结果 res 的步骤从 if 中移动到了 else 中,因为中序遍历的顺序是左-根-右,参见代码如下: 解法三: classSolution {public: vector<int> inorderTraversal(TreeNode*root) { ...