* TreeNode(int x) : val(x), left(NULL), right(NULL) {} * };*/classSolution {public: vector<int> inorderTraversal(TreeNode *root) { vector<int>ret;if(!root)returnret; inorder(root, ret);returnret; }voidinorder(TreeNode* root, vector<int>&ret) {if(root->left) inorder(root-...
class Solution { public: vector<int> inorderTraversal(TreeNode *root) { // Start typing your C/C++ solution below // DO NOT write int main() function vector<int> *p_vec = new vector<int>(); inorderRecur( root, *p_vec); return *p_vec; } void inorderRecur( TreeNode *root, vecto...
Binary Tree Inorder Traversal Given a binary tree, return the inorder traversal of its nodes' values. For example: Given binary tree {1,#,2,3}, 1 \ 2 / 3 return [1,3,2]. Note: Recursive solution is trivial, could you do it iteratively? confused what "{1,#,2,3}" means? > ...
classSolution(object):definorderTraversal(self, root):#递归""":type root: TreeNode :rtype: List[int]"""ifnotroot:return[]returnself.inorderTraversal(root.left) + [root.val] + self.inorderTraversal(root.right) Java解法 classSolution {publicList < Integer >inorderTraversal(TreeNode root) ...
* Given a binary tree, return the inorder traversal of its nodes' values. * * For example: * Given binary tree {1,#,2,3}, * * 1 * \ * 2 * / * 3 * * return [1,3,2]. * * Note: Recursive solution is trivial, could you do it iteratively?
【Inorder Traversal】 Given a binary tree, return theinordertraversal of its nodes' values. For example: Given binary tree{1,#,2,3}, 1 \ 2 / 3 return[1,3,2]. Note:Recursive solution is trivial, could you do it iteratively?
题目: Given preorder and inorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree. 根据前序遍历和中序遍历结果构造二叉树。 思路分析: 分析二叉树前序遍历和中序遍历的结果我们发现: 二叉树前序遍历的第一个节点是根节点。 在中序遍历...
Given a binary tree, return theinordertraversal of its nodes' values. For example: Given binary tree{1,#,2,3}, 1 \ 2 / 3 return[1,3,2]. Note: Recursive solution is trivial, could you do it iteratively? Analysis: 给出一棵二叉树,返回它节点值的中序遍历。
class Solution { public: vector<int> res; vector<int>inorderTraversal(TreeNode* root) {if(root == NULL) return res;if(root ->left != NULL) {inorderTraversal(root ->left); } res.push_back(root ->val);if(root ->right != NULL) ...
Solution classSolution{private:voidrecursiveBuild(TreeNode* &node, vector<int>& preorder,intpstart,intpend, vector<int>& inorder,intistart,intiend){if(pstart > pend)return; node =newTreeNode(preorder[pstart]);if(pstart == pend)return;inti;for(i = istart; i <= iend; i++)if(inord...