Val) // 接下来该处理 cur 的右子树 cur = cur.Right } return ans } 题目链接: Binary Tree Inorder Traversal: leetcode.com/problems/b 二叉树的中序遍历: leetcode.cn/problems/bi LeetCode 日更第 238 天,感谢阅读至此的你 欢迎点赞、收藏鼓励支持小满...
*/publicclassBinaryTreeInOrderTraversal{privateint[] result =null;intpos=0;publicint[] traversal(char[] tree) { result =newint[tree.length]; pos =0; traversalByRecursion(createTree(tree));returnresult; }publicint[] traversal1(char[] tree) { result =newint[tree.length]; pos =0; travers...
Space complexity : O(n)O(n). Approach 3: Morris Traversal In this method, we have to use a new data structure-Threaded Binary Tree, and the strategy is as follows: Step 1: Initialize current as root Step 2: While current is not NULL, If current does not have left child a. Add cu...
{ inorder(root -> right,vec); } } vector<int> inorderTraversal(TreeNode* root) { vector<int> vec; if(root == NULL)return vec; inorder(root,vec); return vec; } }; 链接 记得来给小星星哦,享受解体的快感 github.com/binyi10/leet github.com/binyi10/leet ...
LeetCode: 105. Construct Binary Tree from Preorder and Inorder Traversal 题目描述 Given preorder and inorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree. For example, given ...
原题链接:http://oj.leetcode.com/problems/construct-binary-tree-from-preorder-and-inorder-traversal/ 这道题是树中比較有难度的题目。须要依据先序遍历和中序遍历来构造出树来。这道题看似毫无头绪。事实上梳理一下还是有章可循的。以下我们就用一个样例来解释怎样构造出树。
94. Binary Tree Inorder TraversalEasy Topics Companies Given the root of a binary tree, return the inorder traversal of its nodes' values. Example 1: Input: root = [1,null,2,3] Output: [1,3,2] Explanation: Example 2: Input: root = [1,2,3,4,5,null,8,null,null,6,7,9] ...
名字叫做, morrois traversal, 自己写了下: My code: /** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */publicclassSolution{publicList<Integer>inorderTraversal(TreeNoderoot){List...
Invert/Flip Binary Tree -https://leetcode.com/problems/invert-binary-tree/ Binary Tree Maximum Path Sum -https://leetcode.com/problems/binary-tree-maximum-path-sum/ Binary Tree Level Order Traversal -https://leetcode.com/problems/binary-tree-level-order-traversal/ ...
preorder 的范围 [begin, end] 并不是 inorder 的范围,如果直接拿begin, end 来作为inorder[] 数组的边界条件,就会出错。所以必须要分为两个范围。 [preorderBegin, preorderEnd] [inorderBegin, inorderEnd] 这两个范围。 第二个错误,错的更深,其实到最后都没有彻底意识到,一定要当心,做此类题时。