``` import java.util.ArrayList; import java.util.Arrays; import java.util.List; /** * Source : https://oj.leetcode.com/problems/flatten-binary-tree-to
* Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * };*/classSolution {public:voidflatten(TreeNode *root) {if(!root)return;if(!root -> left)returnflatten(root ->right);...
Can you solve this real interview question? Flatten Binary Tree to Linked List - Given the root of a binary tree, flatten the tree into a "linked list": * The "linked list" should use the same TreeNode class where the right child pointer points to the
* Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: void flatten(TreeNode* root) { if(!root){ return ; } if(root->left) fl...
public void flatten(TreeNode root) { if (root == null) return; flatten(root.left); flatten(root.right); TreeNode p = root; // 递归到叶的父结点,因为叶结点不需要处理 if (p.left == null) {// 左孩子为空,无需处理 return;
* Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */classSolution{public:voidflatten(TreeNode*root){// Start typing your C/C++ solution below// DO NOT write int mai...
flatten(leftNode); flatten(rightNode);}}/** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode() {} * TreeNode(int val) { this.val = val; } * TreeNode(int val, TreeNode left, TreeN...
7、非常规序遍历——二叉树转化为链表:114.Flatten Binary Tree to Linked List Given a binary tree, flatten it to a linked list in-place. For example, given the following tree: 1 / \ 2 5 / \ \ 3 4 6 The flattened tree should look like: 1 \ 2 \ 3 \ 4 \ 5 \ 6 /** * De...
If you notice carefully in the flattened tree, each node's right child points to the next node of a pre-order trave 这道题要求把二叉树展开成链表,根据展开后形成的链表的顺序分析出是使用先序遍历,那么只要是数的遍历就有递归和非递归的两种方法来求解,这里我们也用两种方法来求解。首先来看递归版本的...
来源：力扣（LeetCode） 链接：https://leetcode-cn.com/problems/flatten-binary-tree-to-linked-list/ 著作权归领扣网络所有。商业转载请联系官方授权，非商业转载请注明出处。解法一：递归使用递归的方式求解，递归过程如下：如果当前根节点为null时，直接返回；如果当前根节点的左右子节点都为空时，不需要调整...