Find the Duplicate Number LeetCode:287. Find the Duplicate Number 找到数组中重复多次的那个数(唯一)。 思路一:元素值作索引 从位置0开始遍历数组,每次得到的元素值作为下一个遍历的元素,并且将遍历过的元素置为0,如果存在重复的元素值,那么这个位置的元素肯定会被多次访问,如果访问到的元素值为0则表明这个...
Find the Duplicate Number Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one. Note: You must not modify the array (...
Leetcode 287. Find the Duplicate Number Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one. Note: You must not modify...
Given an arraynumscontainingn+ 1 integers where each integer is between 1 andn(inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one. Note: You must not modify the array (assume the array is read only). Yo...
https://leetcode.com/problems/find-the-duplicate-number/discuss/73045/Simple-C%2B%2B-code-with-O(1)-space-and-O(nlogn)-time-complexity https://leetcode.com/problems/find-the-duplicate-number/discuss/72846/My-easy-understood-solution-with-O(n)-time-and-O(1)-space-without-modifying-the-...
287. Find the Duplicate Number containingn+1integerswhereeachintegerisbetween1andn(inclusive),provethatatleastoneduplicatenumbermustexist.Assumethatthereisonlyoneduplicatenumber,findtheduplicateone leetcode之Find the Duplicate Number 问题 问题描述:Givenanarraynumscontainingn+1integerswhereeachintegerisbetween1...
Assume that there is only one duplicate number, find the duplicate one. 即一个包含n+1个整型的数组,数组元素的大小范围是[1,n],说明至少有一个重复的元素。假设只有一个重复元素,找出这个元素。 Example 1: Input: [1,3,4,2,2] Output: 2 Example 2: Input: [3,1,3,4,2] Output: 3 ...
public int findDuplicate(int[] nums) { int min = 0, max = nums.length - 1; while(min <= max){ // 找到中间那个数 int mid = min + (max - min) / 2; int cnt = 0; // 计算总数组中有多少个数小于等于中间数 for(int i = 0; i < nums.length; i++){ ...
func findDuplicate(nums []int) int { // 二分区间左边界,初始化为 1 l := 1 // 二分区间右边界,初始化为 n r := len(nums) - 1 // 当前区间不为空时,继续二分 for l <= r { // 计算区间中点 mid mid := (l + r) >> 1 // 统计 nums 中小于等于 mid 的数字个数 count := 0...
LeetCode 287. Find the Duplicate Number 简介:给定一个包含 n + 1 个整数的数组 nums,其数字都在 1 到 n 之间(包括 1 和 n),可知至少存在一个重复的整数。假设只有一个重复的整数,找出这个重复的数。 Description Given an array nums containing n + 1 integers where each integer is between 1 and...