Leetcode 287. Find the Duplicate Number Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one. Note: You must not modify...
Leetcode——287. Find the Duplicate Number 题目原址 https://leetcode.com/problems/find-the-duplicate-number/description/ 题目描述 Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one ......
Given an arraynumscontainingn+ 1 integers where each integer is between 1 andn(inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one. Note: You must not modify the array (assume the array is read only). Yo...
https://leetcode.com/problems/find-the-duplicate-number/description/ 287. Find the Duplicate Number Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate ...
链表判环算法见LeetCode 142. Linked List Cycle II. 代码 class Solution { public int findDuplicate(int[] nums) { int slow = 0, fast = 0; do { slow = nums[slow]; fast = nums[nums[fast]]; } while (slow != fast); slow = 0; while (fast != slow) { fast = nums[fast]; ...
Leetcode每日一题:287.find-the-duplicate-number(寻找重复数),思路:一开始并没有什么头绪,直接排序加遍历以O(nlgn)的复杂度水过去了,后来看评论才知道有Floyd判圈算法这么秒的方法,简称龟兔赛跑;具体算法讲解可参考文章:算法-floyd判环(圈)算法,讲得很棒,便于理
Can you solve this real interview question? Find the Duplicate Number - Given an array of integers nums containing n + 1 integers where each integer is in the range [1, n] inclusive. There is only one repeated number in nums, return this repeated number
题目链接: Find the Duplicate Number : leetcode.com/problems/f 寻找重复数: leetcode-cn.com/problem LeetCode 日更第 73 天,感谢阅读至此的你 欢迎点赞、收藏、在看鼓励支持小满 发布于 2022-03-30 07:57 力扣(LeetCode) 算法 二分查找 赞同1添加评论 分享喜欢收藏申请转载...
LeetCode Find the Duplicate Number 找重复出现的数(技巧),题意:有一个含有n+1个元素的数组,元素值是在1～n之间的整数,请找出其中出现超过1次的数。(保证仅有1个出现次数是超过1的数)思路:方法一:O(nlogn)。根据鸽笼原理及题意,每次如果&nums,inttar)//是否在
public int findDuplicate(int[] nums) { int slow = 0; int fast = 0; // 找到快慢指针相遇的地方 do{ slow = nums[slow]; fast = nums[nums[fast]]; } while(slow != fast); int find = 0; // 用一个新指针从头开始,直到和慢指针相遇 ...