Testcase Test Result Test Result 658. Find K Closest ElementsMedium Topics Companies Given a sorted integer array arr, two integers k and x, return the k closest integers to x in the array. The result should also be sorted in ascending order. An integer a is closer to x than an integer...
这里我们只要找到与x最接近的数,然后在这个数两边找k个即可。 代码如下:python:class Solution: def findClosestElements(self, arr: List[int], k: int, x: int) -> List[int]: ind = self.findColestIndex(arr,x) lo = hi = ind res = [arr[ind]] for i in range(k-1): if lo-1<0: ...
classSolution {public: vector<int> findClosestElements(vector<int>& arr,intk,intx) {intleft =0, right = arr.size()-k;while(left<right){intmid = left + (right-left)/2;if(x>arr[mid]){if(x-arr[mid] > arr[mid+k]-x) left= mid+1;elseright=mid; }elseright=mid; }returnvector...
Given a sorted array, two integers k and x, find the k closest elements to x in the array. The result should also be sorted in ascending order. If there is a tie, the smaller elements are always preferred. Example 1: Input: [1,2,3,4,5], k=4, x=3 Output: [1,2,3,4] Exam...
class Solution { public List<Integer> findClosestElements(int[] arr, int k, int x) { int midIndex = 0; // 中心位置 if (x <= arr[0]) return build(arr, 0, k, x); if (x >= arr[arr.length - 1]) return build(arr, arr.length - 1, k, x); for (int i = 0; i < ar...
英文coding面试练习 day2-1 | Leetcode658 Find K Closest Elements, 视频播放量 23、弹幕量 0、点赞数 0、投硬币枚数 0、收藏人数 0、转发人数 0, 视频作者 Rollwithlife, 作者简介 To remember,相关视频:英文coding面试练习 day3-2 | Leetcode907 Sum of Subarray Minim
public List<Integer> findClosestElements(int[] arr, int k, int x) { int midIndex = 0; // 中心位置 if (x <= arr[0]) return build(arr, 0, k, x); if (x >= arr[arr.length - 1]) return build(arr, arr.length - 1, k, x); ...
importheapqclassSolution:deffindClosestElements(self,arr:List[int],k:int,x:int)->List[int]:# No special# Identify the index of x using binary searchleft,right=0,len(arr)-1x_index=-1whileleft<=right:mid=left+(right-left)//2ifarr[left]==arr[mid]andmid!=left:left+=1ifarr[mid]==...
输入:points = [[1,3],[-2,2]], k = 1输出:[[-2,2]]解释:(1, 3) 和原点之间的距离为 sqrt(10), (-2, 2) 和原点之间的距离为 sqrt(8), 由于 sqrt(8) < sqrt(10),(-2, 2) 离原点更近。 我们只需要距离原点最近的 K = 1 个点,所以答案就是 [[-2,2]]。
LeetCode 658 Find K Closest Elements Medium Good question. Using binary search to find the start index of the k window. A obvious characteristic of the final state is that the difference of left element and x should always be less than or equal to that of the right element. So we can ...