# @param head, a ListNode # @return a list node defdetectCycle(self, head): # Detect the loop p1=head p2=head whilep2isnotNone: p1=p1.next ifp2.nextisNone:# No loop returnNone p2=p2.next.next ifp1==p2: break# have a loop ifp2isNone: returnNone # Find the start of the l...
loop = k + m 分析起始点的位置:通过慢指针继续走loop - m步就可以到达环的起始位置,正好k=loop - m,所以,相遇时把快指针指向头指针,两个指针以相同的速度走k步就可以一起到达环的起始位置了。 可以看看这篇文章的解释,看着像我邮学长的blog 3 代码 publicListNodedetectCycle(ListNode head){ListNodefast=...
不加虚拟头节点 /*** Definition for singly-linked list.* public class ListNode {* int val;*...
再次相遇即为环起点代码class Solution(object): def detectCycle(self, head): """ :...
1559.Detect-Cycles-in-2D-Grid (M) 1568.Minimum-Number-of-Days-to-Disconnect-Island (H-) 1617.Count-Subtrees-With-Max-Distance-Between-Cities (H-) 1654.Minimum-Jumps-to-Reach-Home (H-) 1905.Count-Sub-Islands (M+) 2045.Second-Minimum-Time-to-Reach-Destination (M+) 2101.Detonate-the-...
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LeetCode 刷题随手记 - 第一部分 前 256 题(非会员),仅算法题,的吐槽 https://leetcode.com/problemset/algorithms/...
515 Find Largest Value in Each Tree Row 52.70% Medium 516 Longest Palindromic Subsequence 42.00% Medium 517 Super Washing Machines 34.60% Hard 518 Coin Change 2 33.20% Medium 520 Detect Capital 54.20% Easy 521 Longest Uncommon Subsequence I 50.70% Easy 522 Longest Uncommon Subsequence II 28.10% ...