此时,另一个指针沿着环移动到环头需要步数:k*b - c = a;(k >= 1) 所以,两个指针第二次重合必定在环的开头位置。 ListNode *LeetCode::detectCycle(ListNode *head){if(!head)returnnullptr;boolhasCycle =false; ListNode*p = head, *q =head;while(q){ p
142. Linked List Cycle II Given a linked list, return the node where the cycle begins. If there is no cycle, returnnull. To represent a cycle in the given linked list, we use an integerposwhich represents the position (0-indexed) in the linked list where tail connects to. Ifposis-1...
Given a linked list, return the node where the cycle begins. If there is no cycle, return null. To represent a cycle in the given linked list, we use an integer pos which represents the position (0-indexed) in the linked list where tail connects to. If pos is -1, then there is ...
Given a linked list, return the node where the cycle begins. If there is no cycle, return null. To represent a cycle in the given linked list, we use an integer pos which represents the position (0-indexed) in the linked list where tail connects to. If pos is -1, then there is n...
Return true if there is a cycle in the linked list. Otherwise, return false. 英文版地址 leetcode.com/problems/l 中文版描述 给你一个链表的头节点 head ,判断链表中是否有环。如果链表中有某个节点,可以通过连续跟踪 next 指针再次到达,则链表中存在环。 为了表示给定链表中的环,评测系统内部使用整数 ...
和上一道题不一样的是leetcode 141. Linked List Cycle 链表循环的判定 + 双指针,这道题还要求求出环的入口结点。 可以使用双指针来判断是否存在环。两个指针相遇的时候,我们设相遇点为c,此时fp和sp都指向了c,接下来令fp继续指向c结点,sp指向链表头结点head,此时最大的不同是fp的步数变成为每次走一步,令...
141 Linked..判断链表 LinkList 是否带循环。Given a linked list, determine if it has a cycle in it.To represent a cycle in t
0142 Linked List Cycle II Go 46.2% Medium 0143 Reorder List Go 50.9% Medium 0144 Binary Tree Preorder Traversal Go 64.5% Easy 0145 Binary Tree Postorder Traversal Go 66.5% Easy 0146 LRU Cache Go 40.5% Medium 0147 Insertion Sort List Go 50.1% Medium 0148 Sort List Go 54.0% Medium...
141Linked List CyclePython1. Hash or set 2. Two points (fast and slow) 3. Add a max and check if reach the max 142Linked List Cycle IIPythonTwo points, a+b=nr 143Reorder ListPython1. List as index to rebuild relation, O(n) and O(n) ...
* @param head: The first node of linked list. * @return: The node where the cycle begins. * if there is no cycle, return null */ public ListNode detectCycle(ListNode head) { if(head == null || head.next == null) return null; ...