The same repeated number may be chosen fromCunlimited number of times. Note: All numbers (including target) will be positive integers. Elements in a combination (a1,a2, … ,ak) must be in non-descending order. (ie,a1 ≤a2 ≤…≤ak). The solution set must not contain duplicate combinat...
class Solution { public: vector<vector<int>> combinationSum(vector<int>& candidates, int target) { vector<vector<int>> res; vector<int> curr; sort(candidates.begin(), candidates.end()); dfs(res, curr, target, 0, candidates); return res; } void dfs(vector<vector<int>>& res, vector...
代码 1classSolution {2public:3vector<vector<int>> combinationSum(vector<int>& candidates,inttarget) {4sort(candidates.begin(),candidates.end());5vector<vector<int>>res;6vector<int>temp;7if(candidates.size())8combi(candidates,target,temp,res,0);9returnres;10}11voidcombi(vector<int>& candi...
class Solution { public: vector<vector<int>> combinationSum(vector<int>& candidates, int target) { sort(candidates.begin(),candidates.end()); //排序 vector<vector<int>> result; vector<int> combination; for(int i=candidates.size()-1;i>=0;--i)//从最大的元素开始 { combination.push_bac...
The solution set must not contain duplicate combinations. Example 1:Input: candidates = [2,3,6,7], target = 7, A solution set is: [ [7], [2,2,3] ] 我们先来看一下combination sum最基本的例子,从一个无重复元素的数组中,找出所有可以使数字和为target的组合,数组中的数字可以无限制重复被选...
class Solution { public: vector<vector<int>> combinationSum(vector<int>& candidates, int target) { vector<int> temp; vector<vector<int>> result; myCombine(candidates,target,0,temp,result); return result; } void myCombine(vector<int>& candidates, int target,int index,vector<int> & temp,...
class Solution {private: vector<vector<int>> res; void dfs(vector<int> &c, int t, int start, vector<int> &v) { if (!t) { res.push_back(v); return; } for (int i = start; i < c.size() && t >= c[i]; ++i) { v.push_back(c[i]); dfs(...
1publicclassSolution {2publicArrayList<ArrayList<Integer>> combinationSum(int[] candidates,inttarget) {3ArrayList<ArrayList<Integer>> res =newArrayList<ArrayList<Integer>>();4ArrayList<Integer> item =newArrayList<Integer>();5Arrays.sort(candidates);6helper(res, item, candidates, target, 0);7return...
请一键三连, 非常感谢LeetCode 力扣题解377. 组合总和 Ⅳ377. Combination Sum IV帮你深度理解 记忆化搜索算法 深度优先搜索 dfs bfs 广度优先搜索 回溯 暴力枚举, 视频播放量 284、弹幕量 0、点赞数 3、投硬币枚数 2、收藏人数 1、转发人数 0, 视频作者 程序员写代码, 作者
你这题保熟吗 Leetcode每日一题 39. Combination Sum, 视频播放量 45、弹幕量 0、点赞数 3、投硬币枚数 0、收藏人数 0、转发人数 0, 视频作者 你这题保熟吗, 作者简介 每天进步一点点,相关视频:你这题保熟吗 Leetcode 454. 4Sum II,你这题保熟吗 Leetcode 290. Word Patt