所以只第一次取就好了。 View Code SOLUTION 2: 不使用pre来判断也可以,只要判断当前值是不是与上一个值相同,如果相同不取。我们只考虑i = index即可,因为这么多相同的值也只需要取一个 View Code GITHUB: https://github.com/yuzhangcmu/LeetCode_algorithm/blob/master/combination/CombinationSum2_1203.java...
Elements in a combination (a1,a2, … ,ak) must be in non-descending order. (ie,a1 ≤a2 ≤…≤ak). The solution set must not contain duplicate combinations. For example, given candidate set10,1,2,7,6,1,5and target8, A solution set is: [1, 7] [1, 2, 5] [2, 6] [1, 1...
个人博客:http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 方法一:DFS 方法二:回溯法 日期 题目地址:https://leetcode.com/problems/combination-sum-ii/description/ 题目描述 Given a collection of candidate numbers (candidates) and a target number (target), find all uniquecombinationsincandidate...
虽然这个解法在leetcode上是超时的,但是我们把这道题放在这里,并且用backtracking的方法进行解答,主要的目的是介绍在不同条件下,我们是如何应对的combination sum这一系列题目的。 classSolution:defcombinationSum4(self,nums:List[int],target:int)->int:res=[]nums.sort()self.dfs(nums,target,[],res)returnlen...
题目链接:https://leetcode.com/problems/combination-sum-ii/?tab=Description 给定数组,数组中的元素均为正数,target也是正数。(数组中的元素可能有重复) 求出所有的满足求和等于terget的组合。 数组中的元素只能使用一次。(数组中重复的元素可以最多使用重复次数) ...
Combination Sum II 标签: C++ 算法 LeetCode DFS 每日算法——leetcode系列 问题Combination Sum II Difficulty:Medium Given a set of candidate numbers (C) and a target number (T), find all unique combinations inCwhere the candidate numbers sums to T....
classSolution(object):defhelper(self,candidates,target,path,index,result):iftarget==0:result.append(path[:])returnprev=-1foriinrange(index,len(candidates)):ifcandidates[i]>target:breakifprev!=-1andprev==candidates[i]:continueself.helper(candidates,target-candidates[i],path+[candidates[i]],i...
A solution set is: [ [1,7], [1,2,5], [2,6], [1,1,6] ] 1 2 3 4 5 6 这道题与上一道题也就是Combination Sum是类似的题目,不过在上一道题中,元素本身不重复,但是可以重复使用,在第二道题中,元素本身会重复,但是不能重复使用。所以程序结构基本是相似的。比较重要的一个点就是,如果去...
[LintCode/LeetCode] Combination Sum I & II Combination Sum I Problem Given a set of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T. The same repeated number may be chosen ......
原题地址:https://oj.leetcode.com/problems/combination-sum-ii/ 题意: Given a collection of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T. Each number in C may only be used once in the combination. Note: All ...