right=0,1# left=buy, right=sellmaxP=0whileright<len(prices):## 遍历整个 listifprices[right]>prices[left]:## 在存在赚钱机会的条件下profit=prices[right]-prices[left]maxP=max(maxP,profit)else:## 对于任意一个右指针日期,我们都要回顾它后面的所有日期,找出买入的最佳时间点;left+=1## 当右...
LeetCode 121:买卖股票的最佳时机(Best Time to Buy and Sell Stock) 交易次数限制:只允许进行一次买卖操作。这意味着你必须先买入一次然后卖出一次,目标是最大化这一次交易的利润。 目标:找到一次买卖股票的最大利润。如果没有任何交易能够完成,则返回0。 这个问题的核心在于找到价格差最大的一对,其中买入操作发生...
714. Best Time to Buy and Sell Stock with Transaction Fee 方法1:有限状态机的思想(几乎等同于第122题) 方法2:DP思想 121. Best Time to Buy and Sell Stock 给定一个数组,它的第 i 个元素是一支给定股票第 i 天的价格。 如果你最多只允许完成一笔交易(即买入和卖出一支股票一次),设计一个算法来计算...
[LeetCode]Best Time to Buy and Sell Stock 题目:Best Time to Buy and Sell Stock 给定一个数组,数组中一个元素表示一天的股价,求一次交易能得到的最大收益。 思路: 数组可能是多个升序降序组成,只要能找到一组极值,使它们的差最大就可以了。 这样实际上就是每当找到一个极大值,就判断此时的到的差值是否...
https://leetcode.com/problems/best-time-to-buy-and-sell-stock-with-transaction-fee/discuss/108870/Most-consistent-ways-of-dealing-with-the-series-of-stock-problems 读完本文,你可以去力扣拿下如下题目: 买卖股票的最佳时机 买卖股票的最佳时机 II ...
给定一个数组prices,它的第i个元素prices[i]表示一支给定股票第i天的价格。 你只能选择某一天买入这只股票,并选择在未来的某一个不同的日子卖出该股票。设计一个算法来计算你所能获取的最大利润。 返回你可以从这笔交易中获取的最大利润。如果你不能获取任何利润,返回0。
【leetcode】45-best-time-to-buy-and-sell-stock-with-cooldown 力扣 714. 买卖股票的最佳时机包含手续费 开源地址 为了便于大家学习,所有实现均已开源。欢迎 fork + star~ https://github.com/houbb/leetcode 121. 买卖股票的最佳时机 给定一个数组 prices ,它的第 i 个元素 prices[i] 表示一支给定股票第...
Say you have an array for which the ith element is the price of a given stock on day i. If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the stock), design an algorithm to find the maximum profit. Example 1: Input: [7, 1, 5,...
Say you have an array for which theithelement is the price of a given stock on dayi. If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the stock), design an algorithm to find the maximum profit. ...
Say you have an array for which theithelement is the price of a given stock on dayi. If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the stock), design an algorithm to find the maximum profit. ...