LeetCode 122:买卖股票的最佳时机 II(Best Time to Buy and Sell Stock II) 交易次数限制:允许进行多次买卖操作。你可以尽可能地完成更多的交易,但是你不能同时参与多笔交易(即你必须在再次购买前出售掉之前的股票)。 目标:求得最大利润。这里的最大利润是所有可能交易的利润之和。 这个问题的核心在于利用每一
【leetcode】43-best-time-to-buy-and-sell-stock-iv 力扣 188. 买卖股票的最佳时机 IV 【leetcode】44-best-time-to-buy-and-sell-stock-with-cooldown 力扣 309. 买卖股票的最佳时机包含冷冻期 【leetcode】45-best-time-to-buy-and-sell-stock-with-cooldown 力扣 714. 买卖股票的最佳时机包含手续费 ...
【leetcode】43-best-time-to-buy-and-sell-stock-iv 力扣 188. 买卖股票的最佳时机 IV 【leetcode】44-best-time-to-buy-and-sell-stock-with-cooldown 力扣 309. 买卖股票的最佳时机包含冷冻期 【leetcode】45-best-time-to-buy-and-sell-stock-with-cooldown 力扣 714. 买卖股票的最佳时机包含手续费 ...
同样的道理来求f2[i], 只是这里求得是当前max减去当前价格的最大值, f2[i]与f2[i+1]有关 class Solution: # @param prices, a list of integer # @return an integer def maxProfit(self, prices): length=len(prices) if length==0: return 0 f1=[0 for i in range(length)] f2=[0 for i ...
leetcode: Best Time to Buy and Sell Stock III 问题描述: Say you have an array for which the ith element is the price of a given stock on day i. Design an algorithm to find the maximum profit. You may complete at most two tran......
If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the stock), design an algorithm to find the maximum profit. code : 朴素的算法,对每一个i ,计算 最大 的 prices[j] (j>i) 来维护最大的差值,但是这样的复杂度是O(n^2),会TLE ...
If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the stock), design an algorithm to find the maximum profit. 大致的意思就是输入一个股票的股价数组,第i个元素代表第i天的股价,只允许买入卖出一次,问最大的利润是多少?
https://leetcode.com/problems/best-time-to-buy-and-sell-stock-ii/ 因为可以进行无限次交易,并且在下一次buy之前必须已经sell。所以只需要把所有price曲线价格上涨的部分加起来就行。 class Solution(object): def maxProfit(self, prices): """
121. 买卖股票的最佳时机 - 给定一个数组 prices ,它的第 i 个元素 prices[i] 表示一支给定股票第 i 天的价格。 你只能选择 某一天 买入这只股票,并选择在 未来的某一个不同的日子 卖出该股票。设计一个算法来计算你所能获取的最大利润。 返回你可以从这笔交易中获取的
Can you solve this real interview question? Best Time to Buy and Sell Stock - You are given an array prices where prices[i] is the price of a given stock on the ith day. You want to maximize your profit by choosing a single day to buy one stock and choo