binaryTreePath(results,newArrayList<Integer>(), root);returnresults; }publicvoidbinaryTreePath(List<String> results, List<Integer>path, TreeNode cur) {if(cur ==null) {return;//root==null}if(cur.left ==null&& cur.right ==null) {//需要在上层判断 path.add(cur.val);//add cur's valStr...
in : 记录当前的路径 p , 和vector<int>path 相同,只不过一个记录的是 val ,一个记录点的指针。 s : 记录每个节点的 p->right v2s : 将path转换称符合要求的string /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNod...
public List<String> binaryTreePaths(TreeNode root) { if (root != null) { findPath(root, String.valueOf(root.val)); } return strList; } public void findPath(TreeNode p, String path) { if (p.left == null && p.right == null) strList.add(path); if (p.left != null) findPat...
/* * @lc app=leetcode id=124 lang=javascript * * [124] Binary Tree Maximum Path Sum *//** * Definition for a binary tree node. * function TreeNode(val) { * this.val = val; * this.left = this.right = null; * } */function helper(node, payload) { if (node === n...
leetcode 二叉树路径和 path sum 1. Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum. For example: Given the below binary tree andsum = 22,...
left, path); dfs(root.right, path); } } Python 代码 栈 + 循环实现 # Definition for a binary tree node. # class TreeNode: # def __init__(self, val=0, left=None, right=None): # self.val = val # self.left = left # self.right = right class Solution: def binaryTreePaths(...
binaryTreePaths(root.left, path); } } }publicstaticvoidmain(String[] args) {TreeNoderoot=newTreeNode(1);root.left=newTreeNode(2);root.right=newTreeNode(3);root.left.right=newTreeNode(5);for (Stringpath : binaryTreePaths(root)) {System.out.println(path); } }}【每日...
treePathsIn(node,rootPath) if node is leaf res[]=rootpath+node.val return else if node.left treePathsIn(node.left,rootpath+node.val) if node.right treePathsIn(node.right,rootpath+node.val) /** * Definition for a binary tree node. * type TreeNode struct { * Val int * Left *Tree...
funcmaxPathSum(root*TreeNode)int{varmaxSum=math.MinInt32// 全局最大路径和maxGain(root,&maxSum)...
参考: https://shenjie1993.gitbooks.io/leetcode-python/124%20Binary%20Tree%20Maximum%20Path%20Sum.html 我们现在要求最大路径和,那么就要分别得到左右两条路径的最大和。而左路径的最大和为左节点的值加上它左右路径中较大的路径和,右路径最大和为右节点的值加上它左右路径中较大的路径和。 注意:如果...